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morpeh [17]
3 years ago
12

If Mr. Kirwan’s pet Fluffy the Wonder Hamster rides his unicycle at a rate of 5m/s to the

Physics
1 answer:
-BARSIC- [3]3 years ago
4 0
The condition that would induced the seer or observer to see that the pet hamster is moving at 5 m/s is when the train is also moving at that speed. This is because the unicycle will only allow limited vision to the seer thinking that the pet hamster is not moving at that speed. 
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mote1985 [20]
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3 years ago
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A homeowner uses a snowblower to clear his driveway. knowing that the snow is discharged at an average angle of 40° with the hor
Nesterboy [21]

given that snow is projected at an angle of 40 degree

It range is given as a = 19 ft

a = 19 * 0.3048 = 5.8 m

now we can use the formula of horizontal range

R = \frac{v_o^2 sin2\theta}{g}

5.8 =\frac{ v_o^2 sin(2*40)}{9.8}

5.8 = \frac{v_o^2 * sin80}{9.8}

v_o^2 = 57.7

v_o = 7.6 m/s

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8 0
3 years ago
Multiply the following and write your answer using significant figures. What is 25 x 15?
Troyanec [42]
25x15 is 375 cndnmekcivjfndn(sorry it said I needed 20 characters to comment)
3 0
3 years ago
A rock is projected from the edge of the top of a building with an initial velocity of 21.6 m/s at an angle of 37◦ above the hor
dusya [7]
<h2>Horizontal component of the rock’s velocity when it strikes the ground is 17.25 m/s</h2>

Explanation:

In horizontal direction there is no acceleration or deceleration for a rock projected at an initial angle of 37° off the ground.

So the horizontal component of velocity always remains the same.

Horizontal component of velocity is the cosine component of velocity.

Initial velocity, u = 21.6 m/s

Angle, θ = 37°

Horizontal component of velocity = u cosθ

Horizontal component of velocity = 21.6 cos37

Horizontal component of velocity = 17.25 m/s

Since the horizontal velocity is unaffected, we have

    Horizontal component of the rock’s velocity when it strikes the ground = 17.25 m/s

5 0
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mihalych1998 [28]

Answer:

A

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