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emmasim [6.3K]
3 years ago
7

Which compound is more soluble in an acidic solution than in a neutral solution?

Chemistry
1 answer:
Nady [450]3 years ago
8 0

Answer : Salt is more soluble in an acidic solution than in an neutral solution.

Explaination : In an acidic solution molecules of salt are assaociated with hydrogen bonding whereas in neutral solutions it molecules are not assaociated with hydrogen bonding. Acidic solution is a type of solution which has higher concentration of hydrogen ions than water is called acidic solution for ex: water.

Neutral solution is a solution which has a pH of 7,it is neither acidic nor basic but it is middle so that is called neutral solution.

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A(n) _______ is an organic compound in which a carbonyl group is bonded to a nitrogen atom. (2 points)
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By pipet, 11.00 mL of a 0.823 MM stock solution of potassium permanganate (KMnO4) was transferred to a 50.00-mL volumetric flask
tangare [24]

Answer:

1) 0.18106 M is the molarity of the resulting solution.

2) 0.823 Molar is the molarity of the solution.

Explanation:

1) Volume of stock solution = V_1=11.00 mL

Concentration of stock solution = M_1=0.823 M

Volume of stock solution after dilution = V_2=50.00 mL

Concentration of stock solution after dilution = M_2=?

M_1V_1=M_2V_2 ( dilution )

M_2=\frac{0.823 M\times 11.00 mL}{50 ,00 mL}=0.18106 M

0.18106 M is the molarity of the resulting solution.

2)

Molarity of the solution is the moles of compound in 1 Liter solutions.

Molarity=\frac{\text{Mass of compound}}{\text{Molar mas of compound}\times Volume (L)}

Mass of potassium permanganate = 13.0 g

Molar mass of potassium permangante = 158 g/mol

Volume of the solution = 100.00 mL = 0.100  L ( 1 mL=0.001 L)

Molarity=\frac{13.0 g}{158 g/mol\times 0.100 L}=0.823 mol/L

0.823 Molar is the molarity of the solution.

6 0
3 years ago
How many molecules of Na are in 3.2 moles of Na?
pav-90 [236]

Answer: 1.9 x 10²⁴ molecules Na

Explanation: To solve for the molecules of Na, we will use the Avogadro's number.

3.2 moles Na x 6.022 x10²³ molecules Na/ 1 mole Nà

= 1.9 x 10²⁴ molecules Na

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3 years ago
What is the pH of a 0.08 M solution of Ca(OH),?
torisob [31]

Answer:

pH = 12.20

Explanation:

Ca(OH)2 is a strong base, so it dissociates completely. A 0.08 M solution of Ca(OH)2 is 0.16 M OH-, since every mole of Ca(OH)2 has 2 OH-.

Calculate pOH using [OH-] = 0.16 M

pOH = -log(0.16) = 0.80

pH = 14 - pOH = 14 - 0.80 = 12.20

4 0
3 years ago
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