Answer:
Anode:
3Mg(s) ----------> 3Mg2+(aq) + 6e
Cathode:
2Al3+(aq) +6e ---------> 2Al(s)
Explanation:
Anode:
3Mg(s) ----------> 3Mg2+(aq) + 6e
Cathode:
2Al3+(aq) +6e ---------> 2Al(s)
Magnesium is more electro positive than aluminum hence it functions as the anode. Six electrons are lost/gained in the redox process as shown in the oxidation and reduction half reaction equations above. Magnesium is oxidized to magnesium ion while aluminum is reduced to elemental aluminum.
Answer:
Density = 7.11 g.cm⁻³
Solution:
Density is given as,
Density = Mass / Volume --------- (1)
Data Given;
Mass = 32 g
Volume = 16.8 mL - 12.3 mL = 4.5 mL = 4.5 cm³
Putting values in equation 1,
Density = 32 g / 4.5 cm³
Density = 7.11 g.cm⁻³
Answer:
D
Explanation:
Isotopes are identified by their mass, which is the total number of protons and neutrons.
Answer:
1:1
Explanation:
The ratio of metal cationic atom to non-metal anionic atom in the compound is 1:1.
This is an ionic compound.
- This is because metal cationic atom has two valence electrons.
- Non-metal anionic oxygen has six valence electrons
- Calcium loses two of its valence electrons to be isoelectronic with Ar and this confers a stable configuration to it.
- Non-metal oxygen atom accepts the electrons and adds 2 to its 6 electrons to become isoelectronic with neon.
- So, 1 metal cationic atom combines with 1 non-metal anionic atom to form the compound.
I acually habe no idea but I nust want to point out that my toast's brand is Sarah Lee lol
