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adoni [48]
2 years ago
15

Which of the following compounds would be more soluble in 1 M NH3 than in pure water? BaSO 4 AgBr Pbl 2 BaF 2 Ca(OH) 2

Chemistry
1 answer:
Kazeer [188]2 years ago
8 0

Answer:

AgBr

Explanation:

The salt, AgBr has a very low solubility is pure water. However, it has a high solubility in 1 M NH3. The reason behind this higher solubility of AgBr in 1 M aqueous ammonia solution is the formation of a complex as shown below;

AgBr(s) + 2NH3(aq) ----> [Ag(NH3)2]^+(aq) + Br^-(aq)

The formation of this linear silver diammine complex accounts for the higher solubility of AgBr in 1 M aqueous ammonia solution.

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sasho [114]

I would say it is answer choice C, Laws are based on proven hypothesis by many different scientists.

4 0
2 years ago
How many mol of hydrogen are needed to double the volume occupied by 0.34 mol of hydrogen,
natima [27]

Answer:

0.68

Explanation:

Number of moles is directly propotionalto the volume at standard condition.

6 0
3 years ago
A weak acid (ha) has a pka of 4.001. If a solution of this acid has a ph of 4.110, what percentage of the acid is not ionized? (
OverLord2011 [107]

99.9224 % of the acid is not ionized.

____HA + H₂O ⇌ A⁻ + H₃O⁺

I: ___<em>c</em> ________0 ____0  

C: _-α<em>c</em> _______+α<em>c</em> __+α<em>c </em>

E: <em>c</em>(1-α) _______α<em>c</em> ___α<em>c </em>

pH = 4.110

[H₃O⁺] = α<em>c</em> = 10^(-4.110) mol/L = 7.76 × 10⁻⁵ mol/L

α = 7.76 × 10⁻⁵

1 – α = 1 - 7.76 × 10⁻⁵ = 0.999 224 = 99.9224 %

7 0
3 years ago
........URGENT PLEASE HELP............
Yuri [45]

Answer:

12.0778

Explanation:

6 0
2 years ago
What is the enthalpy of combustion (per mole) of C4H10 (g)? 
Artemon [7]
The balanced chemical reaction for the complete combustion of C4H10 is shown below:

                    C4H10 + (3/2)O2 --> 4CO2 + 5H2O

The enthalpy of formation are listed below:
          C4H10: -2876.9 kJ/mol
              O2:   none (because it is pure substance)
             CO2: -393.5 kJ/mol
             H2O: -285.8 kJ/mol

The enthalpy of combustion is computed by subtracting the total enthalpy formation of the reactants from that of the products.

               ΔHc = (4)(-393.5 kJ/mol) + (5)(-285.8 kJ/mol) - (-2876.9 kJ/mol)
                       = -<em>126.1 kJ</em>

Thus, the enthalpy of combustion of the carbon is -126.1 kJ. 
5 0
3 years ago
Read 2 more answers
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