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marissa [1.9K]
3 years ago
10

What causes the mechanical advantage of the inclined plane to be less than that of the lever

Physics
1 answer:
kondor19780726 [428]3 years ago
5 0
An inclined plane has less of a mechanical advantage because it has to have more work to take so,etching up than down. I hope this makes sense.
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If a car has a kinetic energy of 40000 J and is moving at a velocity of 25 m/s, what is the mass of the car? KE=1/2mv
ohaa [14]

Answer:

3200 Kg

Explanation:

Just apply the formula:

40.000 = 1/2 . m . 25

80.000 = 25m

m = 80.000/25

m = 3200 Kg

7 0
3 years ago
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zloy xaker [14]

Answer:

Explanation:

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4 0
3 years ago
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A small 1.0 kg steel ball rolls west at 3.0 m/s collides with a large 3.0 kg ball at rest. After the collision, the small ball m
77julia77 [94]

Answer:

The direction of the momentum of the large ball after the collision with respect to east is 146.58°.

Explanation:

Given that,

Mass of large ball = 3.0 kg

Mass of steel ball = 1.0 kg

Velocity = 3.0 kg

After collision,

Velocity = 2.0 m/s

Using conservation of momentum

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

3.0\times0+1.0\times(3.0)(-i)=1.0\times2(-j)+3.0\times v_{2}

-3i+2j=3.0\times v_{2}

v_{2}=-i+0.66j

The direction of the momentum

tan\theta=\dfrac{0.66}{-1}

\theta=tan^{-1}\dfrac{0.66}{-1}

\theta=-33.42^{\circ}

The direction of the momentum with respect to east

\theta=180-33.42=146.58^{\circ}

Hence, The direction of the momentum of the large ball after the collision with respect to east is 146.58°.

7 0
3 years ago
You lift a 25-kg child 0.80 m, slowly carry him 10 m to the playroom, and finally set him back down 0.80 m onto the playroom flo
maksim [4K]

To solve this problem we will apply the work theorem which is expressed as the force applied to displace a body. Considering that body strength is equivalent to weight, we will make the following considerations

\text{Mass of the child} = m = 25kg

\text{Acceleration due to gravity} = g = 9.81m/s^2

\text{Height lifted} = h = 0.80m (Upward)

Work done to upward the object

W = mgh

W = (25)(9.81)(0.8)

W = 196.2J

Horizontal Force applied while carrying 10m,

F = 0N

W = 0J

Height descended in setting the child down

h' = -0.8m (Downwoard)

W = mgh'

W = (25)(9.81)(-0.80)

W = -196.2J

For full time, assuming that the total value of work is always expressed in terms of its symbol, it would be zero, since at first it performs the same work that is later complemented in a negative way.

6 0
4 years ago
What are the units for impulse?<br><br> m/s<br><br> Kg<br><br> Ns<br><br> Newtons
Elodia [21]

Answer:

Kg.m/s is the unit for impulse

Explanation:

If i were wrong please correct me.

7 0
3 years ago
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