If V has a magnitude of 14 units and the same direction qs a vector 3i+6j+2k find v
1 answer:
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<h2>Answer: 10615 nm</h2>
Explanation:
This problem can be solved by the Wien's displacement law, which relates the wavelength where the intensity of the radiation is maximum (also called peak wavelength) with the temperature
of the black body.
In other words:
<em>There is an inverse relationship between the wavelength at which the emission peak of a blackbody occurs and its temperature.</em>
Being this expresed as:
(1)
Where:
is in Kelvin (K)
is the <u>wavelength of the emission peak</u> in meters (m).
is the <u>Wien constant</u>, whose value is
From this we can deduce that the higher the black body temperature, the shorter the maximum wavelength of emission will be.
Now, let's apply equation (1), finding :
(2)
Finally:
This is the peak wavelength for radiation from ice at 273 K, and corresponds to the<u> infrared.</u>
The two possible angles obtained by using the qudratic equation are;
θ = 15.10° and θ2 = 73.51°
Given, speed of water = = 50ft/s
For the motion along x direction, time period can be calculated as follows:
35 = (50 × cosθ) t
t = 0.64 / cosθ
For the motion in y direction, an equation can be obtained as follows:
θ)
Plugging in the values we get:
θ)
-20 = -32tanθ - 10.304θ
Upon solving the above quadratic equation, we get,
tanθ = 0.27 , -3.38
Therefore,
tanθ = 0.27
θ = 15.10°
and, tanθ = -3.38
θ = 73.51
Learn more about quadratic equation here:
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