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3 years ago

If V has a magnitude of 14 units and the same direction qs a vector 3i+6j+2k find v

Physics

1 answer:

melomori [17]3 years ago

7 0

Answer:

v = 6i + 12j + 4k

Explanation:

Find the magnitude of the direction vector.

√(3² + 6² + 2²) = 7

Normalize the direction vector.

3/7 i + 6/7 j + 2/7 k

Multiply by the magnitude of v.

v = 14 (3/7 i + 6/7 j + 2/7 k)

v = 6i + 12j + 4k

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NemiM [27]

Answer:

a) $F_H=776.952\ N$

b) $F_g=706.32\ N$

c) $v=5.4249\ m.s^{-1}$

d) $KE=1059.48\ J$

Explanation:

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mass of the astronaut, $m=72\ kg$

vertical displacement of the astronaut, $h=15\ m$

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Here the lift force is the resultant of the force of gravity being overcome by the force of helicopter.

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$F_g=$ force of gravity

$F_H=72\times 0.981+72\times9.81$

$F_H=776.952\ N$

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$F_g=m.g$

$F_g=72\times 9.81$

$F_g=706.32\ N$

Since the astronaut has been picked from an ocean we assume her initial velocity to be zero, $u=0\ m.s^{-1}$

using equation of motion:

$v^2=u^2+2a.h$

$v^2=0^2+2\times 0.981\times 15$

$v=5.4249\ m.s^{-1}$

Hence the kinetic energy:

$KE=\frac{1}{2} m.v^2$

$KE=0.5\times 72\times 5.4249^2$

$KE=1059.48\ J$

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If V has a magnitude of 14 units and the same direction qs a vector 3i+6j+2k find v​

If V has a magnitude of 14 units and the same direction qs a vector 3i+6j+2k find v