k =
k = (6.626×10-¹⁹/590 × 10-⁹ )^{2} /2 × 1.673 × 10-²⁷
k = (1.12 × 10-³⁰)^2/3.346×10-²⁷
k = 1.25 × 10-⁶⁰ /3.346×10-²⁷
k = 0
ldk why, my answer is coming this :(
If V has a magnitude of 14 units and the same direction qs a vector 3i+6j+2k find v
1 answer:
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Answer:
Approximate linear dimension is 2 light years.
Explanation:
Radius of the spiral galaxy r = 62000 LY
Thickness of the galaxy h = 700 LY
Volume of the galaxy = πr²h
= (3.14)(62000)²(700)
= (3.14)(62)²(7)(10)⁸
= 84568×10⁸
= (LY)³
Since galaxy contains number of stars = 1078 billion stars ≈
Now volume covered by each star of the galaxy =
=
= 7.839 Light Years
Now the linear dimension across the volume
=
=
= 1.99 LY
≈ 2 Light Years
Therefore, approximate linear dimension is 2 light years.