Answer:
The correct option is d ( Neither A nor B)
Explanation:
Technician A made 2 mistakes in his statement.Firstly the tire is self supporting not self sealing.
Secondly, this tire does not provide permanent sealing of punctured area option a is incorrect.
This self-supporting tire after being affected with complete air leakage can temporarily bear the load of the car and avoid rolling over a distance of 80 km at a maximum speed of 55 mph. Here is what technician B suggested incorrectly as the tire after being.Here the technician B suggested incorrectly as the tire after being affected with puncture can not travel at any speed so option B is wrong
Since option a and b are incorrect and c is invalid.
Answer:
Explanation:
We can solve Von Karman momentum integral equation as seen below using following in the attached file
Answer:
98,614.82 W/m²
Explanation:
Where;
Q = the amount of heat loss from the pipe
h = the heat transfer coefficient of the pipe = 50 W/m².K
T₁ = the ambient temperature of the pipe = 30⁰C
T₂ = the outside temperature of the pipe = 100⁰C
L= the length of pipe
r₁ = inner radius of the pipe = 20mm
r₂ = outer radius of the pipe = 25mm
To determine the amount of heat loss from the pipe per unit length
From the equation above
= 98,614.82 W/m²
Answer: for ideal situation
T2 = 16.5158K
Work = - 11.4J
For appropriate generalization correlation
T2 = 308.57K
Work = 177.797MJ
Explanation:detailed calculation and explanation is shown in the image below.
Answer:
Space velocity = 30 hr⁻¹
Explanation:
Space velocity for reactors express how much reactor volume of feed or reactants can be treated per unit time. For example, a space velocity of 3 hr⁻¹ means the reactor can process 3 times its volume per hour.
It is given mathematically as
Space velocity = (volumetric flow rate of the reactants)/(the reactor volume)
Volumetric flowrate of the reeactants
= (molar flow rate)/(concentration)
Molar flowrate of the reactants = 300 millimol/hr
Concentration of the reactants = 100 millimol/liter
Volumetric flowrate of the reactants = (300/100) = 3 liters/hr
Reactor volume = 0.1 liter
Space velocity = (3/0.1) = 30 /hr = 30 hr⁻¹
Hope this Helps!!!
