Ask question

Ask question

All categories

4 years ago

9

Which conditions would result in the worst soil for growing crops?

2 answers:

alexira [117]4 years ago

6 0

D. A little rainfall and high temperatures

lisov135 [29]4 years ago

5 0

D. little rainfall and high temperatures!

You might be interested in

How does physical weathering happen?

Ilya [14]

Answer:

Physical weathering is caused by the effects of changing temperature on rocks, causing the rock to break apart. The process is sometimes assisted by water. Freeze-thaw occurs when water continually seeps into cracks, freezes and expands, eventually breaking the rock apart

Explanation:

4 0

3 years ago

How many cheeks do you have?

belka [17]

Realyyy,,,,,,,,,,, 4 ig

4 0

4 years ago

Read 2 more answers

Every chemical reaction involves a change in

madam [21]

A chemical reaction is when you cant change something back to the way it was before

6 0

4 years ago

Which of the following particles has almost no mass? proton neutron electron

ahrayia [7]

<u>Answer:</u> Electron has almost no mass.

<u>Explanation:</u>

Mass is defined as the actual matter that is contained in a substance. At an atomic level, it is expressed in atomic mass units.

The given options are the 3 subatomic particles.

Mass of the given subatomic particles are:

Proton = 1.007276u

Neutron = 1.008664u

Electron = 0.0005485u

Mass of neutron is slightly more than the mass of proton.

From the above information, it is visible that electron has a negligible mass.

Hence, the correct answer is electron.

5 0

4 years ago

A first-order reaction has a half-life of 29.8 s . How long does it take for the concentration of the reactant in the reaction t

lutik1710 [3]

Answer : The time taken for the concentration of the reactant in the reaction to fall to one-fourth of its initial value is, 12.4 seconds.

Explanation :

Half-life = 29.8 s

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{29.8s}$

$k=0.0232s^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $0.0232s^{-1}$

t = time passed by the sample = ?

a = let initial amount of the reactant = x M

a - x = amount left after decay process = $x-\frac{1}{4}\times (x)=\frac{3}{4}\times (X)=\frac{3x}{4}M$

Now put all the given values in above equation, we get

$t=\frac{2.303}{0.0232s^{-1}}\log\frac{x}{(\frac{3x}{4})}$

$t=12.4s$

Therefore, the time taken for the concentration of the reactant in the reaction to fall to one-fourth of its initial value is, 12.4 seconds.

7 0

4 years ago