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kompoz [17]
3 years ago
6

How much heat will be released if 9.75 g of aluminum reacts with excess ammonium nitrate (NH₄NO₃) according to the following equ

ation? 2 Al (s) + 3 NH₄NO₃ (s) ---> 3 N₂ (g) + 6 H₂O (g) + Al₂O₃ (s) ΔH = -2030 kJ *
Chemistry
1 answer:
Mandarinka [93]3 years ago
7 0

Not enough info

tffffff

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Vitek1552 [10]

Answer:

Metal is copper.

Explanation:

Mass of a metal, m = 54 g

Heat energy required, Q = 773 J

The temperature changes from 63.0 °C to 100.0 °C.

We need to identify the metal. Heat required to raise the temperature is given by :

Q=mc\Delta T

c is specific heat of the metal

We can identify the metal by finding its specific heat.

c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{773}{54\times (100-63)}\\\\=0.386\ J/g^{\circ} C

The metal is copper. Its specific heat is 0.386\ J/g^{\circ} C.

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