Answer:
The break force that must be applied to hold the plane stationary is 12597.4 N
Explanation:
p₁ = p₂, T₁ = T₂
The heat supplied = 
× Heating value of jet fuel
The heat supplied = 0.5 kg/s × 42,700 kJ/kg = 21,350 kJ/s
The heat supplied = 
· 
= 20 kg/s
The heat supplied = 20* = 21,350 kJ/s
= 1.15 kJ/kg
T₃ = 21,350/(1.15*20) + 485.03 = 1413.3 K
p₂ = p₁ × p₂/p₁ = 95×9 = 855 kPa
p₃ = p₂ = 855 kPa
T₃ - T₄ = T₂ - T₁ = 485.03 - 280.15 = 204.88 K
T₄ = 1413.3 - 204.88 = 1208.42 K
T₅ = 1208.42*(2/2.333) = 1035.94 K
= √(1.333*287.3*1035.94) = 629.87 m/s
The total thrust = × 
= 20*629.87 = 12597.4 N
Therefore;
The break force that must be applied to hold the plane stationary = 12597.4 N.
Answer:
The minimum thickness t of the wall is 0.00446 mm
Explanation:
Solution
Given that
Pressure =670kPa = 0.670
σ allowable normal stress = 150 MPa
Inner diameter = 2mm
Steel = A516 grade 60
Now,
Since the hoop stress is twice the longitudinal stress, the cylindrical tank is more likely to fail from the hoop stress.
Thus
σ allowable = σₙ = pμ/t
=p (d/2)
150 MPa =0.670MPa * 2/2/t
=0.67/t
t=0.67/150
t =0.00446 mm
Answer:
1.498 m
Explanation:
Electric potential due to a point charge V = K × Q / r
4.8 × 10 ⁴ V = 8.99 × 10⁹ N.m²/C² × 8 × 10⁻⁶ C / r
r = 8.99 × 10⁹ N.m²/C² × 8 × 10⁻⁶ C / 4.8 × 10 ⁴ V = 1.498 m
Answer:
A. Yes
B. Yes
Explanation:
We want to evaluate the validity of the given assertions.
1. The first statement is true
The sine rule stipulates that the ratio of a side and the sine of the angle facing the side is a constant for all sides of the triangle.
Hence, to use it, it’s either we have two sides and an angle and we are tasked with calculating the value of the non given side
Or
We have two angles and a side and we want to calculate the value of the side provided we have the angle facing this side in question.
For notation purposes;
We can express the it for a triangle having three sides a, b, c and angles A,B, C with each lower case letter being the side that faces its corresponding big letter angles
a/Sin A = b/Sin B = c/Sin C
2. The cosine rule looks like the Pythagoras’s theorem in notation but has a subtraction extension that multiplies two times the product of the other two sides and the cosine of the angle facing the side we want to calculate
So let’s say we want to calculate the side a in a triangle of sides a, b , c and we have the angle facing the side A
That would be;
a^2 = b^2 + c^2 -2bcCosA
So yes, the cosine rule can be used for the scenario above
