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DanielleElmas [232]
3 years ago
8

What simple machine can be described as a shaft that is attached to the center of a wheel?

Physics
1 answer:
charle [14.2K]3 years ago
4 0
"Wheel & Axle" <span>can be described as a shaft that is attached to the center of a wheel

Hope this helps!</span>
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65 POINTS! PLEASE ANSWER EVERY QUESTION! NEED HELP ASAP!
otez555 [7]
Maybe you can split up the questions. I will try to answer your first question.

1. In an elastic collision, momentum is conserved. The momentum before the collision is equal to the momentum after the collision. This is a consequence of Newton's 3rd law. (Action = Reaction)

2. Momentum: p = m₁v₁ + m₂v₂

m₁ mass of ball A
v₁ velocity of ball A
m₂ mass of ball B
v₂ velocity of ball B

Momentum before the collision:
p = 2*9 + 3*(-6) = 18 - 18 = 0

Momentum after the collision:
p = 2*(-9) + 3*6 = -18 + 18 = 0

3: mv + m(-v) = m(-v) + m(v)
the velocities would reverse.

4.This question is not factual since the energy of an elastic collision must also be conserved. The final velocities should be: v₁ = -1 m/s and v₂ = 5 m/s. That said assuming the given velocities were correct:
before collision
p = 10*3 + 5*(-3) = 30 - 15 = 15
after collision:
p = 10*(-2) + 5 * v₂ = 15
v₂ = 7

5.You figure out.



3 0
3 years ago
A solid block, with a mass of 0.15kg, on a frictionless surface is pushed directly onto a horizontal spring, with a spring const
iren [92.7K]

Answer:

16.1 m/s

Explanation:

We can solve the problem by using the law of conservation of energy.

At the beginning, the spring is compressed by x = 35 cm = 0.35 m, and it stores an elastic potential energy given by

U=\frac{1}{2}kx^2

where k = 316 N/m is the spring constant. Once the block is released, the spring returns to its natural length and all its elastic potential energy is converted into kinetic energy of the block (which starts moving). This kinetic energy is equal to

K=\frac{1}{2}mv^2

where m = 0.15 kg is the mass of the block and v is its speed.

Since the energy must be conserved, we can equate the initial elastic energy of the spring to the final kinetic energy of the block, and from the equation we obtain we can find the speed of the block:

\frac{1}{2}kx^2=\frac{1}{2}mv^2\\v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(316 N/m)(0.35 m)^2}{0.15 kg}}=16.1 m/s

4 0
3 years ago
A small first-aid kit is dropped by a rock climber who is descending steadily at 1.9 m/s. After 2.4 s, what is the velocity of t
Genrish500 [490]

Answer:

v=-21.65 m/s

Explanation:

From the exercise we have:

v_{o}=1.9m/s\\ g=9.81 m/s^{2}\\ t=2.4s

To find the velocity after 2.4s we need to use the following formula:

v=v_{o}+gt

v=1.9m/s-(9.81m/s^{2})(2.4s)=-21.65m/s

The negative sign means that the kit is going down.

6 0
3 years ago
Read 2 more answers
Is energy made or lost over time
Ann [662]

Well basically in physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant, it is said to be conserved over time. This law means that energy can neither be created nor destroyed, it can only be transformed or transferred from one form to another.


Hope this helps (:

5 0
3 years ago
Which of the following pairs of charged particles will result in a repelling force acting between the particles?
Maslowich
A and C because if both particles are alike they repel kind of like a magnet 
when two magnets are both the same side they repel
6 0
3 years ago
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