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klasskru [66]
3 years ago
12

What is the density at 27 °C of 28.0 milliliters of a liquid that has a mass of 4.05 grams?

Chemistry
1 answer:
ddd [48]3 years ago
5 0

Answer:

4.05/28=0.144g/ml

Explanation:

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A gas occupies 5.31 liters at a pressure of 0.55 atm. Determine the volume at standard pressure.
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Answer:

Option A; V =  2.92 L

Explanation:

If we assume a lot of things, like:

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The temperature is constant.

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Then we have the relation:

P*V = n*R*T = constant.

Where:

P = pressure

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n = number of moles

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T = temperature.

We know that when P = 0.55 atm, the volume is 5.31 L

Then:

(0.55 atm)*(5.31 L) = constant

Now, when the gas is at standard pressure ( P = 1 atm)

We still have the relation:

P*V = constant = (0.55 atm)*(5.31 L)

(1 atm)*V = (0.55 atm)*(5.31 L)

Now we only need to solve this for V.

V = (0.55 atm/ 1 atm)*(5.31 L) = 2.92 L

V = 2.92 L

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