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4 years ago

5 minute deadline List 2 academic and Scientific applications of radiation

Physics

1 answer:

Harrizon [31]4 years ago

3 0

Academic- affect on substances, how it works
Scientific- helping cancer, making weapons

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A police car is driving down the street with it's siren on. You are standing still on the sidewalk beside the street. If the fre

diamong [38]

Answer:

A) 1568.60 Hz

Explanation:

This change is frequency happens due to doppler effect

The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source

$f_(observed)=\frac{(c+-V_r)}{(C+-V_s)} *f_(emmited)\\$

where

C = the propagation speed of waves in the medium;

Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;

Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.

A) Here the Source is moving towards the receiver(C-Vs)

and the receiver is standing still (Vr=0) therefore the observed frequency should get higher

$f_(observed)=\frac{C}{C-V_s} *f_(emmited)\\=\frac{343}{343-15}*1500\\ =1568.60 Hz$

6 0

3 years ago

. All synthetic materials ultimately come from

zvonat [6]

it is actually natural resources

6 0

4 years ago

If the ankylosaurs starts running and accelerates at 1.3m/s^2 for 3 seconds how far does he make it before the velociraptor catc

sveta [45]

Acceleration is the change of velocity, and velocity is the change of distance. The opposite of finding change, or differentiation, is integration.

Acceleration = 1.3 m/s²

Velocity: ∫ 1.3 dx = 1.3x + c m/s

Distance: ∫ 1.3x dx = 1.3x²/2 + c m

Distance run: 1.3*3²/2 = 5.85 m

What bad thing happened?

7 0

3 years ago

With time running out in a game, Rachel runs towards the basket at a speed of 2.5 meters per second and from half-court, launche

finlep [7]

Answer:

Rachel(2.5,0)

ball(6.5,4.7)

b.R=10.15m/s, 27.57deg

Explanation:

The reference angle of Rachel is 0 $0^{0} while the ball is at 36^{0}$

resolving rachel's speed to the horizontal, we have

Ux=2.5cos0

Ux=2.5m/s

resolving rachel's speed to the vertical we have,

Uy=2.5sin0

Uy=0

for the ball

resolving the speed to its horizontal component

Ux=8cos36

Ux=6.5m/s

Uy=8sin36

Uy=4.7m/s

Rachel(2.5,0)

ball(6.5,4.7)

To get the resultant of their speed

Add the horizontal speed of rachel to that of the ball to get the total horizontal speed

Add the vertical speed of rachel and the ball to get the total vertical speed component

TUx=2.5+6.5=9M/S

TUy=0+4.7=4.7m/s

R= $\sqrt{(TUx^2+TUy^2}$

R= $\sqrt{(9^2+4.7^2}$

R= $\sqrt{(103)}$

R=10.15m/s

the direction

tan $\alpha$ =TUy/TUx

tan $\alpha$ =4.7/9

$\alpha$ =tan^-1(0.522)

$\alpha$ =27.57deg

4 0

3 years ago

kykrilka [37]

Answer:

<h2>n+5 is ur answer</h2>

hope it helps uh.

6 0

3 years ago