Explanation:
Mass of the ball, m = 0.058 kg
Initial speed of the ball, u = 11 m/s
Final speed of the ball, v = -11 m/s (negative as it rebounds)
Time, t = 2.1 s
(a) Let F is the average force exerted on the wall. It is given by :
F = 0.607 N
(b) Area of wall,
Let P is the average pressure on that area. It is given by :
P = 0.202 Pa
Hence, this is the required solution.
Answer:
The force of kinetic friction between the block and the floor is 2.4 N
Explanation:
The given parameters are;
The weight of the block = 8 Newtons
The velocity of the block = Constant velocity
Taking the kinetic friction for wood, = 0.3, we have;
The normal reaction of the block on horizontal ground, N = The weight of the block = 8 N
The force of kinetic friction between , =
× N
Therefore, we have;
The force of kinetic friction between the block and the floor, = 0.3 × 8 N = 2.4 N.