Answer:
when CO2 gas is passed through lime water it turns milky due to the formation of calcium carbonate which formula is CaCO3.
Ca(OH)2+ CO2------ CaCO3
when excess of carbon dioxide is passed through calcium carbonate calcium hydrogen carbonate is formed and solution become colourless.
CaCO3+CO2------ Ca(HCO3)
To calculate the mass of Fe formed in a) we get first the limiting reactant between Fe2O3 and CO. Given the masses, the ratio of Fe2O3 is 1.33 while that of CO is 1.67. Hence the limiting reagent is Fe2O3. The mass of Fe formed is 148.98 grams. In b, the needed CO is only 112.04 grams. Hence, the excess is 27. 96 grams.
Answer:
A) M = 100X
B) M = 36X
C) M = 178.88X
Explanation:
Given data:
ASTM grain size number 7
a) total grain per inch^2 - 64 grain/inch^2
we know that number of grain per square inch is given as

where M is magnification, n is grain size
therefore we have

solving for M we get
M = 100 X
B) total grain per inch^2 = 500 grain/inch^2
we know that number of grain per square inch is given as

where M is magnification, n is grain size
therefore we have
solving for M we get
M = 36 X
C) Total grain per inch^2 = 20 grain/inch^2
we know that number of grain per square inch is given as

where M is magnification, n is grain size
therefore we have
solving for M we get
M = 178.88 X
The benzoic acid Collect the top layer dry with Na2SO4 and evaporate the solvent.
Benzoic acid is sparingly soluble in water and forms a precipitate. The benzoic acid can then be separated by suction filtration through a Buchner funnel. Washing with sodium bicarbonate converts the benzoic acid to the more water-soluble form of sodium benzoate, which is extracted into the aqueous layer. Additionally, sodium bicarbonate neutralizes the catalytic acid in this reaction.
Benzoic acid containing the naphthalene impurity can be purified by crystallization in water. The reaction between benzoic acid and NaOH is an acid-base neutralization reaction. An acid reacts with a base to form salt and water. In aqueous solutions, NaOH increases the solubility of benzoic acid. Benzoic acid cannot move from one layer to another because ethanol is immiscible with water.
Learn more about Benzoic acid here:-brainly.com/question/28299797
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<u>Correct Answer:</u><u> Option (A) </u>
H₂S : SO₂ = 2:2 and,
O₂: H₂O = 3:2
Explanation:
The mole ratio is the ratio of coefficients of the compounds involved in the reaction. <u>R</u><u><em>eactants,</em></u><u> as on the left hand side of the chemical reaction which reach to for</u>m new products.
In the given reaction,
2H₂S + 3O₂ ⇒ 2SO₂ + 2H₂O
<u>The reactants are :</u> H₂S (hydrogen sulphide) & O₂ (oxygen)
<u>The products are :</u> SO₂ (sulphur dioxide) & H₂O (water)
- 2 moles of hydrogen sulphide react with 3 moles of oxygen
- 2 moles of sulphur dioxide & 2 moles of water are produced
Therefore correct option is
H₂S : SO₂ = 2:2 and,
O₂: H₂O = 3:2