Question

Shani poses as the Statue of Liberty for an art class. She holds a torch above her head with her right hand and a book against her side with her left hand. She holds the pose for ten minutes. At the end of the session, she mentions to her friend that it was a lot of work to pose and that her arms are really tired.
Which describes the work Shani did while she posed?

A: She did more work with her right hand than with her left because the right was held up higher.
B: She did no work while she posed because she did not move the torch or the book.
C: She did work while she posed because she was tired at the end of the session.
D: She did no work while she posed because she did not exert a force on anything.

Answer 1

Hi there! I think the answer is letter A). She did more work with her right hand than with her left because the right was held up higher. The question was asking what best describes the work Shani did while she posed. The description of her work was holding a torch on the right hand lifting it above, and the left was holding a book against her side. Her right hand did more work, because it was lifted higher. 

Answer 2

Answer:

B. She did no work while she posed because she did not move the torch or the book.

Explanation:

In physics, work done is defined as the product of force and displacement.

                                         W = Fd         ………… (i)

Equation (i) shows that Work done will be zero if either force or displacement is zero. In the current scenario, Shani just holds torch and book in her right and left hand respectively. She applied force to hold them but torch and book have not covered any distance. Hence, the work done will be zero.