Answer:
Explanation:
The amplitude of a wave refers to the maximum amount of displacement of a particle on the medium from its rest position.
Missing detail in the text:
"<span>A small glass bead has been charged to + 25 nC "
Solution
The force exerted on a charge q by an electric field E is given by
</span>
![F=qE](https://tex.z-dn.net/?f=F%3DqE)
<span>Considering the charge on the bead as a single point charge, the electric field generated by it is
</span>
![E=k_e \frac{Q}{r^2}](https://tex.z-dn.net/?f=E%3Dk_e%20%20%5Cfrac%7BQ%7D%7Br%5E2%7D%20)
with
![k_e = 8.99\cdot 10^9 Nm^2/C^2](https://tex.z-dn.net/?f=k_e%20%3D%208.99%5Ccdot%2010%5E9%20Nm%5E2%2FC%5E2)
,
![Q=+25 nC=25 \cdot 10^{-9}C](https://tex.z-dn.net/?f=Q%3D%2B25%20nC%3D25%20%5Ccdot%2010%5E%7B-9%7DC)
is the charge on the bead. We want to calculate the field at
![r=4.0 cm=0.04 m](https://tex.z-dn.net/?f=r%3D4.0%20cm%3D0.04%20m)
:
![E=(8.99\cdot 10^9) \frac{25\cdot 10^{-9}}{(0.04)^2}=1.4\cdot 10^5 V/m](https://tex.z-dn.net/?f=E%3D%288.99%5Ccdot%2010%5E9%29%20%5Cfrac%7B25%5Ccdot%2010%5E%7B-9%7D%7D%7B%280.04%29%5E2%7D%3D1.4%5Ccdot%2010%5E5%20V%2Fm%20)
The proton has a charge of
![q=1.6\cdot 10^{-19}C](https://tex.z-dn.net/?f=q%3D1.6%5Ccdot%2010%5E%7B-19%7DC)
, therefore the force exerted on it is
![F=qE=1.6\cdot 10^{-19}C \cdot 1.4\cdot 10^5 V/m=2.25\cdot 10^{-14} N](https://tex.z-dn.net/?f=F%3DqE%3D1.6%5Ccdot%2010%5E%7B-19%7DC%20%5Ccdot%201.4%5Ccdot%2010%5E5%20V%2Fm%3D2.25%5Ccdot%2010%5E%7B-14%7D%20N)
And finally, we can use Newton's second law to calculate the acceleration of the proton. Given the proton mass,
![m=1.67\cdot 10^{-27} kg](https://tex.z-dn.net/?f=m%3D1.67%5Ccdot%2010%5E%7B-27%7D%20kg)
, we have
![F=ma](https://tex.z-dn.net/?f=F%3Dma)
![a= \frac{F}{m}= \frac{2.25\cdot 10^{-14} N}{1.67\cdot 10^{-27} kg}=1.35 \cdot 10^{13} m/s^2](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7BF%7D%7Bm%7D%3D%20%5Cfrac%7B2.25%5Ccdot%2010%5E%7B-14%7D%20N%7D%7B1.67%5Ccdot%2010%5E%7B-27%7D%20kg%7D%3D1.35%20%5Ccdot%2010%5E%7B13%7D%20m%2Fs%5E2%20)
The charge on the bead is positive, and the proton charge is positive as well, therefore the proton is pushed away from the bead, so:
Answer:
a = g (m₂ -m₁ sin θ) / (m₁ + m₂)
Explanation:
To solve this we must locate a reference system in the inclined plane, in this case the axis eg. it is parallel to the plane and the axis and is perpendicular to the plane, we take the direction to the right as positive.
Let's write Newton's second law for block 1 on the plane
X axis
T - Wₓ = m₁ a
Y Axis
N –
= 0
We use trigonometry to find the components of the weight
sin θ = Wₓ / W
Wₓ = W sin θ
cos θ = W_{y} / W
W_{y}= W cos θ
We substitute
T - m₁ g sin θ = m₁ a
N = m₁ g cos θ
We write Newton's equations for block 2 that is hanging.
Note that if block 1 goes up, block 2 must go down, therefore for this block the positive direction is down.
W₂ - T = m₂ a
Let's write the system of equations
T - m₁ g sin θ = m₁ a
m₂ g - T = m₂ a
Let's add
m₂ g - m₁ g sin θ = (m₂ + m₁) a
a = g (m₂ -m₁ sin θ) / (m₁ + m₂)
Acceleration is the same for both blocks as they are connected by a rope
the answer is B your welcome
In order to answer either of these, we need to know the energy content of coal ... like kwh (or joules or BTU) in each kilogram (or pound or ton) of coal.