The answer is: 4.00 mol of Fe(OH)2 is produced.
Balanced chemical reaction:
Fe(s) + 2NiO(OH)(s) + 2H₂O(l) → Fe(OH)₂(s) + 2Ni(OH)₂(aq).
n(Fe) = 5.00 mol; amount of iron.
n(NiO(OH)) = 8.00 mol; amount of nickel oxide hydroxide, limiting reactant.
From chemical reaction: n(NiO(OH)) : n(Fe(OH)₂) = 2 : 1.
n(Fe(OH)₂) = 8 mol ÷ 2.
n(Fe(OH)₂) = 4 mol; amount of iron(II) hydroxide.
Answer:
7.16x10⁻⁸M = [Ag+]
Explanation:
Using the equation:
E(Cell) =E⁰ - 0.0592/2 • log ([Cu2+]/[Ag+]²)
<em>Where E</em>⁰<em>= 0.4249V</em>
<em>E(Cell) = -(-0.0019V) -Measured value-</em>
<em>[Cu2+] = 1M</em>
<em />
Replacing:
0.0019V = 0.4249V - 0.0592/2 • log (1M/[Ag+]²)
-0.423V = - 0.0296 • log (1M/[Ag+]²)
14.29 = log (1M/[Ag+]²)
1.95x10¹⁴ = 1M / [Ag+]²
[Ag+]² = 5.12x10⁻¹⁵M
7.16x10⁻⁸M = [Ag+]
Answer:
magnesium + hydrochloride -> magnesium chloride + hydroxide
Explanation: