Answer:
Explanation:
THE QUESTION SHOULD BE
Write the equilibrium constant expression, Kc, for the following reaction: If either the numerator or denominator is 1, please enter 1 CaCO3(s).
CaCO3(s) <=> Ca2+(aq) + CO32-(aq)
Write the mathematical form of the concentration of the products, then divide it by the concentration of the reactants as follows
Kc =[Ca2+]^1 . [CO32-]^1 / [CaCO3]^1
Answer:
3rd option. 1–butanamine
Explanation:
To name the compound above, the following must be observed:
1. Locate the functional group in the chain. In this case the functional group is amine.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound. In this case, the longest chain has 4 carbon i.e butane.
3. Since the functional group is amine, the parent name becomes butanamine i.e replacing the –e at the end in butane with –amine
4. Indicate the position of the functional group in the chain. In this case the functional group is at carbon 1
5. Name the compound by putting the above together.
The name of the compound is:
1–butanamine or butan–1–amine
Answer:
+/- 0.00033
Explanation:
For a 95 % confidence interval the range is given by
+/- Z * s/sqrt(n)
where Z value is 1.916 for a 95% confidence interval
Therefore the interval is
s is the standard deviation in this case 0.0015
n is 75 the number of outposts
calculating,
+/- 1.916 * 0.0015/sqrt(75) = +/- 0.00033
We have to solve this question using the stoichiometry of the reaction:
The equation of the reaction is;
According to the question;
Number of moles of CO2 released = 21.3 g/44 g/mol = 0.48 moles
From the stoichiometry of the reaction:
Since;
24 moles of CO2 released 15,026 KJ
0.48 moles of CO2 will release 0.48 * 15,026/24
= 301 KJ of heat.
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