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3 years ago

Dimension of young modulus

Physics

2 answers:

Lisa [10]3 years ago

6 0

Answer:

$M/LT^2$

Explanation:

Young's modulus is basically the ability of an object to resist change in its length when undergoes a tension or compression. It is a mechanical property of an object.

Now the formula for young's modulus or the modulus of elasticity is:

Young's modulus = Stress/Strain

As we know, strain is a dimensionless quantity, because it is a change in dimension divided by the original dimension, whereas stress has the same dimensions as pressure. Stress is

Stress = Force/Area

Now

Force = ma,

Where m = mass

a = acceleration

So, Stress = (ma)/Area

Acceleration = Velocity/Time

and Velocity = Distance/Time

So Acceleration = (Distance/Time)/Time

Now, what we have to understand here, is the basic dimensions are

M = mass

L = Length (or distance)

T = Time

So, by putting values for dimensions of stress

Stress (Dimensions) = Force/Area

Since Area = (meter)^2

Stress (Dimensions) = Force/L^2

substituting values for force

Stress (Dimensions) = ma/L^2

For mass dimension is M

Stress (Dimensions) = Ma/L^2

for acceleration, dimensions are L/T^2

Stress (Dimensions) = M(L/T^2)/L^2

by simplifying:

Stress (Dimensions) = $M/LT^2$

As we know that dimensions for Young's modulus will be same as the dimensions for Stress, So

Young's Modulus (Dimensions) = $M/LT^2$

Lostsunrise [7]3 years ago

4 0

Answer:

IDK leave me alone !

Explanation:

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Dimension of young modulus​

Dimension of young modulus