Dimension of young modulus
2 answers:
Answer:
Explanation:
Young's modulus is basically the ability of an object to resist change in its length when undergoes a tension or compression. It is a mechanical property of an object.
Now the formula for young's modulus or the modulus of elasticity is:
Young's modulus = Stress/Strain
As we know, strain is a dimensionless quantity, because it is a change in dimension divided by the original dimension, whereas stress has the same dimensions as pressure. Stress is
Stress = Force/Area
Now
Force = ma,
Where m = mass
a = acceleration
So, Stress = (ma)/Area
Acceleration = Velocity/Time
and Velocity = Distance/Time
So Acceleration = (Distance/Time)/Time
Now, what we have to understand here, is the basic dimensions are
M = mass
L = Length (or distance)
T = Time
So, by putting values for dimensions of stress
Stress (Dimensions) = Force/Area
Since Area = (meter)^2
Stress (Dimensions) = Force/L^2
substituting values for force
Stress (Dimensions) = ma/L^2
For mass dimension is M
Stress (Dimensions) = Ma/L^2
for acceleration, dimensions are L/T^2
Stress (Dimensions) = M(L/T^2)/L^2
by simplifying:
Stress (Dimensions) =
As we know that dimensions for Young's modulus will be same as the dimensions for Stress, So
Young's Modulus (Dimensions) =
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Answer:
Option B
Explanation:
Magnification of Microscope is
Mo= Magnification of objective lens and
Me= magnification of the eyepiece.
Both magnifications( of objective and eyepiece) are inversely proportional to the focal length.
Magnification,
when the focal length is less magnification will be high and when the magnification is the low focal length of the microscope will be more.
Thus. Magnification will increase by decreasing the focal length.
The correct answer is Option B
Answer:
Fnet - Fg
Explanation:
When an object is in an elevator, its weight varies with respect to the direction of movement of the elevator and the elevators acceleration.
The weight, W, of an object can be expressed as;
W = mg
where m is the object's mass, and g is the acceleration due gravity.
If the object is in an elevator that speed up, an apparent weight would be felt since both mass and elevator are moving against gravitational pull of the earth.
So that,
= mg + ma
where: mg is the weight of the object, and ma is the apparent weight.
Apparent weight (ma) = - mg