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IceJOKER [234]
3 years ago
7

Dimension of young modulus​

Physics
2 answers:
Lisa [10]3 years ago
6 0

Answer:

M/LT^2

Explanation:

Young's modulus is basically the ability of an object to resist change in its length when undergoes a tension or compression. It is a mechanical property of an object.

Now the formula for young's modulus or the modulus of elasticity is:

Young's modulus = Stress/Strain

As we know, strain is a dimensionless quantity, because it is a change in dimension divided by the original dimension, whereas stress has the same dimensions as pressure. Stress is

Stress = Force/Area

Now

Force = ma,

Where m = mass

           a = acceleration

So, Stress = (ma)/Area

Acceleration = Velocity/Time

and Velocity = Distance/Time

So Acceleration = (Distance/Time)/Time

Now, what we have to understand here, is the basic dimensions are

M = mass

L = Length (or distance)

T = Time

So, by putting values for dimensions of stress

Stress (Dimensions) =  Force/Area

Since Area = (meter)^2

Stress (Dimensions) = Force/L^2

substituting values for force

Stress (Dimensions) = ma/L^2

For mass dimension is M

Stress (Dimensions) = Ma/L^2

for acceleration, dimensions are L/T^2

Stress (Dimensions) = M(L/T^2)/L^2

by simplifying:

Stress (Dimensions) = M/LT^2

As we know that dimensions for Young's modulus will be same as the dimensions for Stress, So

Young's Modulus (Dimensions) = M/LT^2

Lostsunrise [7]3 years ago
4 0

Answer:

IDK leave me alone !

Explanation:

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A 1500 kg car drives around a flat, 50 m diameter track, starting from rest. The drive wheels supply a small but steady 525 N fo
krok68 [10]

Answer:

No. of revolutions before the car slides off is 2

Solution:

As per the question:

Mass of the car, m = 1500 kg

Diameter of the track, d = 50 m

Force, F = 525 N

Coefficient of static friction, \mu_{s} = 0.90

Now,

The acceleration in the tangential direction is given by:

F = ma_{T}

525 = 1500\times a_{T}

a_{T} = 0.35\ m/s^{2}

Here, the centripetal force is given by the friction force:

\frac{mv^{2}}{R} = \mu mg

Thus

v = \sqrt{\mu gR} = \sqrt{0.90\times 9.8\times 25} = 14.849\ m/s

Time taken by the car is given by:

v = v' + at

v' = initial velocity = 0

Thus

t = \frac{v}{a} = \frac{14.849}{0.35} = 42.426\ s

Total Distance covered, d is given by:

v^{2} = v'^{2} + 2ad

14.849^{2} = 0^{2} + 2\times 0.35d

d = 341.99 m

Distance covered in 1 revolution is the circumference of the circle, d' = 2\pi R

Now, the no. of revolutions is given by:

n = \frac{d}{d'} = \frac{314.99}{2\pi \times 25} = 2

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3 years ago
What makes some chemical bonds more stable than others
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it occurs when the energy of the combination has lower energy than the separated atoms

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What type of machine is used to measure the location of an earthquake epicenter.
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Seismometer

Explanation:

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Heike Onnes noticed that pure, solid _____ could be cooled to 4.2 K and have no resistance.
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Point charge μC is located at x =, y = , point charge is located at x = 0m. What are (a)the magnitude and (b)direction of the to
pishuonlain [190]

Answer: The question has some details missing. here is the complete question ; Point charge 1.5 μC is located at x = 0, y = 0.30 m, point charge -1.5 μC is located at x = 0 y = -0.30m. What are (a)the magnitude and (b)direction of the total electric force that these charges exert on a third point charge Q = 5.0 μC at x = 0.40 m, y = 0

Explanation:

  • a) First of all find the distance between the two charges;
  • x = 0, y = 0.30  and x = 0.40 m, y = 0
  • r = √( 0.4² + 0.3²)
  • = 0.5m

hence, the force F = 2Kq1q2cosθ /r²...............equation 1

but cosθ = y/r = 0.3/0.5

cosθ = 0.6

plugging back to equation 1;

F = 2 x 9 x 10^9 x 1.5 x 10^-6 x 5 x 10^-6 /0.5^2

F = 540 x 10^-3

Magnitude of Force = 0.54N

b) Direction is at angle 90

6 0
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