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GalinKa [24]
3 years ago
11

If the velocity of the incident charged particle were doubled, how would b have to change (keeping all other parameters constant

to keep the trajectory of the particle the same?
Physics
1 answer:
Paraphin [41]3 years ago
6 0
If you double the velocity you would have to halve the magnetic field strength to keep the force on the particle the same and hence the trajectory.

F = qvB
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A 20kg mass approaches a spring at a speed of 30 m/s. The mass compresses the spring 12cm before coming to a stop. Calculate the
Oksana_A [137]

Answer:

625000 N/ m

Explanation:

m= 20 kg

v= 30 m/s

x= 12 cm

k = ?

Here when the mass when hits at spring its speed is

Vi= 30 m/s

Finally it comes to rest after compressing for 12 cm

i-e Vf = 0 m/s

Distance= S= 12 cm = 0.12 m

using

2aS= Vf2 - Vi2

==> 2a ×0.12 = o- 30 × 30

==> a = 900 ÷ 0.24 = 3750 m/sec2

Now we know;

F = ma

F= -Kx

==> ma= -kx

==> 20 × 3750 = -K × 0.12

==> k = 625000 N/ m

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3 years ago
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Answer:

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sergiy2304 [10]

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Determine whether each of the statements below is true or false, and place it in the appropriate bin. Objects with equal speeds
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After laboring through this one, I'm wondering if there can possibly be any more ways to say the same thing.

7 0
3 years ago
In models of magnetic and electric fields, why are field vectors depicted by arrows?
taurus [48]

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Learn more: brainly.com/question/102477

7 0
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