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GalinKa [24]
3 years ago
11

If the velocity of the incident charged particle were doubled, how would b have to change (keeping all other parameters constant

to keep the trajectory of the particle the same?
Physics
1 answer:
Paraphin [41]3 years ago
6 0
If you double the velocity you would have to halve the magnetic field strength to keep the force on the particle the same and hence the trajectory.

F = qvB
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Answer:

Explanation:

Given that;

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The  formula for the induced emf is

E = \frac{\Delta  \phi}{\Delta  t}

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E=\frac{\Delta (BA) }{\Delta  t}

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substitute

\texttt {substitute}\  \frac{1}{2} \Delta \theta R^2 \ \ for \Delta  A

E=B\frac{(\Delta  \theta R^3/2)}{\Delta  t} \\\\=\frac{1}{2} BR^2\omega

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E=\frac{1}{2} \times (B\sin \theta)R^2\omega\\\\E=\frac{1}{2} \times (B\sin \theta)(\frac{L}{2} )\omega

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