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4 years ago

10

Which of the following are not part of the stages in cognitive development? A.Sensorimotor B.Concrete C.Formal D.Semi-formal E.F

ormal operational

1 answer:

Bess [88]4 years ago

4 0

The answer is concrete (b)

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working alongside the pharmacist , one of the duties a medication reconciliation technician would perform is to a ) deal with va

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2 years ago

Two parallel metal plates are at a distance of 8.00 m apart.The electric field between the plates is uniform directed towards th

yuradex [85]

Answer:

C

Explanation:

Formula E=F/C also E=V/d

In this case use the second formula; E=V/d

Data given; E=4N/C d=8m

So v=E X d

V=4x8=32V

k.e=eV= 2X32=64eV

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4 years ago

Imagine two billiard balls on a pool table. Ball A has a mass of 2 kilograms and ball B has a mass of 3 kilograms. The initial v

ratelena [41]

1. The balls move to the opposite direction but the same speed. This represents Newton's third law of motion.
2. The total momentum before and after the collision stays constant or is conserved.
3. If the masses were the same, the velocities of both balls after the collision would exchange.
4 and 5. Use momentum balance to solve for the final velocities.

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4 years ago

Read 2 more answers

Acceleration due to gravity is stated as a constant which is given 9.8 m/s2. Many scientists have planned and design experiments

stich3 [128]

The answer is 98.1 m/s2.

3 0

3 years ago

The Jurassic Park ride at Universal Studios theme park drops 25.6 m straight down essentially from rest. Find the time for the d

ankoles [38]

Answer:

V=22.4m/s;T=2.29s

Explanation:

We will use two formulas in order to solve this problem. To determine the velocity at the bottom we can use potential and kinetic energy to solve for the velocity and use the uniformly accelerated displacement formula:

$mgh=\frac{1}{2}mv^{2}\\\\X= V_{0}t-\frac{gt^{2}}{2}$

Solving for velocity using equation 1:

$mgh=\frac{1}{2}mv^{2} \\\\gh=\frac{v^{2}}{2}\\\\\sqrt{2gh}=v\\\\v=\sqrt{2*9.8\frac{m}{s^2}*25.6m}=22.4\frac{m}{s}$

Solving for time in equation 2:

$-25.6m = 0\frac{m}{s}t-\frac{9.8\frac{m}{s^{2}}t^{2}}{2}\\\\-51.2m=-9.8\frac{m}{s^{2}}t^{2}\\\\t=\sqrt{\frac{51.2m}{9.8\frac{m}{s^{2}}}}=2.29s$

7 0

3 years ago