Answer:
An Educated Guess
Explanation:
After the scientist is done with the experiment he should do an educated guess, they use the data from the experiments to make charts and graphs to communicate the results of the experiment. After the scientists makes the hypothesis, they perform this procedure.
Answer:
The weight-average molar mass of polystyrene is 134,160 g/mol.
Explanation:
Molar mass of the monomer styrene ,
, M=104 g/mol
Given , number average molar mass of the polymer , M'= 89,440 g/mol
Degree of polymerization = n

The weight-average molar mass = 
Molar mass dispersity is ratio of weight-average molar mass to the number average molar mass of the polymer.



The weight-average molar mass of polystyrene is 134,160 g/mol.
Answer : The age of the artifact is, 
Explanation :
Half-life = 5715 years
First we have to calculate the rate constant, we use the formula :


Now we have to calculate the time taken to decay.
Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = time taken by sample = ?
a = initial activity of the reactant = 58.2 counts per minute
a - x = activity left after decay process = 42.8 counts per minute
Now put all the given values in above equation, we get


Therefore, the age of the artifact is, 
<h3><u>Answer;</u></h3>
Molar mass
<h3><u>Explanation</u>;</h3>
- Stoichiometry involves the study of quantitative relationships between the amounts of reactants used and products formed by a chemical reaction.
- A conversion factor is a ratio of coefficients found in a balanced reaction, which can be used to inter-convert the amount of products and reactants.
- Molar ratios, or conversion factors, identify the number of moles of each reactant needed to form a certain number of moles of each product.
Answer : The entropy change of reaction for 1.62 moles of
reacts at standard condition is 217.68 J/K
Explanation :
The given balanced reaction is,

The expression used for entropy change of reaction
is:

![\Delta S^o=[n_{Br_2}\times \Delta S_f^0_{(Br_2)}+n_{F_2}\times \Delta S_f^0_{(F_2)}]-[n_{BrF_3}\times \Delta S_f^0_{(BrF_3)}]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo%3D%5Bn_%7BBr_2%7D%5Ctimes%20%5CDelta%20S_f%5E0_%7B%28Br_2%29%7D%2Bn_%7BF_2%7D%5Ctimes%20%5CDelta%20S_f%5E0_%7B%28F_2%29%7D%5D-%5Bn_%7BBrF_3%7D%5Ctimes%20%5CDelta%20S_f%5E0_%7B%28BrF_3%29%7D%5D)
where,
= entropy change of reaction = ?
n = number of moles
= standard entropy of formation
= 245.463 J/mol.K
= 202.78 J/mol.K
= 292.53 J/mol.K
Now put all the given values in this expression, we get:
![\Delta S^o=[1mole\times (245.463J/K.mole)+3mole\times (202.78J/K.mole)}]-[2mole\times (292.53J/K.mole)]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo%3D%5B1mole%5Ctimes%20%28245.463J%2FK.mole%29%2B3mole%5Ctimes%20%28202.78J%2FK.mole%29%7D%5D-%5B2mole%5Ctimes%20%28292.53J%2FK.mole%29%5D)

Now we have to calculate the entropy change of reaction for 1.62 moles of
reacts at standard condition.
From the reaction we conclude that,
As, 2 moles of
has entropy change = 268.74 J/K
So, 1.62 moles of
has entropy change = 
Therefore, the entropy change of reaction for 1.62 moles of
reacts at standard condition is 217.68 J/K