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Olenka [21]
4 years ago
15

Determine if the phrases below are true for catabolic pathways only, anabolic pathways only,or can apply to both pathways, by so

rting the phrases into the three bins. Each phrase can only be used once. Items (9 items) (Drag and drop into the appropriate area below At least one enzyme is regulated All reactions are catalyzed by One or more reactions are endergonic without ATP Consumes more ATP than it Supplies NADH for oxidative Can require reducing ager Pathway produces more ATP than it consumes produces phosphorylation (ieNADPH) Metabolic pathways Catabolic only Both
Chemistry
1 answer:
Ivan4 years ago
6 0

Answer:

<u>Catabolic pathways;</u>

Pathway produces more ATP than it consumes

Supplies NADH for oxidative phosphorylation

<u>Anabolic pathways only</u>:

Consumes more ATP than it produces

Can require reducing agent

<u>Both pathways;</u>

At least one enzyme is regulated

All reactions are catabolized by enzymes

One or more reactions are endergonic without ATP

Explanation:

<u>Catabolic pathways;</u>

Complete oxidation of glucose and then produces more ATP. Oxidative phosphorylation is an example of catabolic pathway.

From the given following conversions are considered as catabolic pathways.

Pathway produces more ATP than it consumes

Supplies NADH for oxidative phosphorylation

<u>Anabolic pathways:</u>

Anabolic pathways produces new molecules and it requires energy in the form of ATP for the formation of new bonds.

From the given following conversions are considered as anabolic pathways.

Consumes more ATP than it produces

Can require reducing agent.

<u>Both pathways;</u>

Metabolic pathways are occuring in the cell only few enzymes are regulate these pathways.

At least one enzyme is regulated

All reactions are catabolized by enzymes

One or more reactions are endergonic without ATP

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What is vapor pressure in science definition?

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We will use the Clausius-Clapeyron equation,

ln(P2/P1) = dHvap/R[1/T1-1/T2]

where,

P1 = unknown

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T1 = 30 oC = 30 + 273 = 303 K

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Feed values,

ln(1/P1) = 39300/8.314[1/303 - 1/351.3]

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