Answer:
x = 0.45*28/3 = 4.2 g
Explanation:
showing work
N2 = 28 g/mole
3Mg + N2 → Mg3N2
3moles .. 28 g
0.45 moles .. x
x = 0.45*28/3 = 4.2 g (answer)
In the question, the number of atoms per unit cell is required for:
A) Polonium (Po)
In polonium, the structure is simple cubic, meaning there are 8 corner atoms, which add up to one atom per unit cell.
B) Manganese (Mn)
The structure of the Mn can be considered to be a body centered cubic (BCC) and the number of atoms for this is 8 corner atoms and 1 central atoms, making a total of 2 atoms per unit cell.
C) Silver (Ag)
Silver has a face centered cubic (FCC) unit cell structure, where there are 8 corner atoms and 6 atoms on the faces, so there are a total of 4 atoms per unit cell.
The balanced equation for the neutralisation reaction is as follows
Ca(OH)₂ + H₂SO₄ ---> CaSO₄ + 2H₂O
stoichiometry of Ca(OH)₂ to H₂SO₄ is 1:1
equivalent number of acid reacts with base
number of H₂SO₄ mol reacting - 2 mol
according to molar ratio of 1:1
number of Ca(OH)₂ mol = number of H₂SO₄ moles
therefore number of Ca(OH)₂ moles required - 2 mol
Now, if i remember this correctly, since i havent had a chemistry class in over 6 or so years
first you want the mass of baking powder in SI units,
why? -- well because molar mass unit conversions are generally in grams per mole
now, 1 oz = 28.3495 grams
now, assuming the "reactants" are the sodium ion and the hydrogen carbonate ion, you need to determine how many components of each will create one component of baking powder
well, if you look at the chemical compound, it requires one Na+ and one HCO3 -
hence the conversion would be 1 mol Na+ + 1 mol HCO3- ->1 mol NaHCO3
now, the big question is
I have 6oz of NaHCO3, but how many moles is that equal to?
now this is where molar mass is required (if you dont know what a mole is, i suggest looking it up, it has to do with a number of atoms in order to get a specific value)
now, the atomic weight of a sodium ion is 23 au
therefore the Molar mass of a sodium ion is 23 g/mol
the atomic weight of HCO3 is 61 au (i think)
hence the molar mass (MM) is 61 g/mol
the atomic weight of NaHCO3 is 84 au
hence the MM of NaHCO3 is 84 g/mol
now going back to the balanced equations
1 mol Na+ + 1 mol HCO3- ->1 mol NaHCO3
1 +1 ->1
but if we multiply each mol by its respective molar mass, we get
23 g Na+ + 61g HCO3- -> 84g NaHCO3
from here, if you wanted to find the amount of each "reactant" in oz,
its just a bunch of proportions