Answer:
The number of germanium atoms per cubic centimeter for this germanium-silicon alloy is 3.16 x 10²¹ atoms/cm³.
Explanation:
Concentration of Ge (
) = 15%
Concentration of Si (C
) = 85%
Density of Germanium (ρ
) = 5.32 g/cm³
Density of Silicon (ρ) = 2.33 g/cm³
Atomic mass of Ge (A)= 72.64 g/mol
To calculate the number of Ge atoms per cubic centimeter for the alloy, we will use the formula:
No of Ge atoms/cm³=[Avogadro's Number*]/([*A/ρ)+(C*A/ρ)]
= (6.02x10²³ * 15%) / [(15% * 72.64/5.32)+(72.64*85%/2.33)]
= (9.03x10²²)/(2.048+26.499)
= (9.03x10²²)/(28.547)
No of Ge atoms/cm³ = 3.16 x 10²¹ atoms/cm³
Answer:
See below
Explanation:
<u>Check One-Sample T-Interval Conditions</u>
Random Sample? √
Sample Size ≥30? √
Independent? √
Population Standard Deviation Unknown? √
<u>One-Sample T-Interval Information</u>
- Formula -->
- Sample Mean -->
- Critical Value -->
(given 
degrees of freedom at a 95% confidence level) - Sample Size -->
- Sample Standard Deviation -->
<u>Problem 1</u>
The critical t-value, as mentioned previously, would be , making the 95% confidence interval equal to 
This interval suggests that we are 95% confident that the true mean levels of lead in soil are between 381.5819 and 398.9181 parts per million (ppm), which satisfies the EPA's regulated maximum of 400 ppm.
Answer:
3.11 A
Explanation:
Use the given relations between power, horsepower, voltage, and current to find the current requirement for the motor.
P = hp(745.7 W) = (1/2)(745.7 W) = 372.85 W
I = P/V = (372.85 W)/(120 V) = 3.1071 A
The amperage required is about 3.11 A.
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According to O*NET, the common work contexts for Licensing Examiners and Inspectors include:
1. Telephone
2. Face-to-face discussions
3. Contact with others
4. Importance of being exact or accurate.
Read more on work contexts here: brainly.com/question/22826220
Answer:
Cite two important additional refinements that resulted from the Wave-mechanical
atomic model.
