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Leno4ka [110]
4 years ago
14

7 Consider two homogeneous bodies of

Physics
1 answer:
kupik [55]4 years ago
3 0

Answer:

No, it is not necessary for them to have same mass.

Explanation:

Let both bodies have a density d1 and d2 respectively.

Since their volumes are equal V1 = V2

we know that,

density = \frac{mass}{volume}

Hence, d1 = \frac{m1}{V1} and d2 = \frac{m2}{V2}  

Taking the ratio of densities,we get

\frac{d1}{d2} = \frac{m1}{m2}

This implies that unless the bodies have same densities, the mass of the two bodies will not be same.

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A long, thin straight wire with linear charge density ? runs down the center of a thin, hollow metal cylinder of radius R. The c
MaRussiya [10]

Answer:

a. E = \frac{\lambda }{(2\epsilon * r) }

b. E = \frac{3(lambda)}{2\pi*\epsilon(outside)  }

Explanation:

The important thing to remember is to use Gauss Law. This is a relation that describes the distribution of electric charge to the resultant electric field.

Linear charge density means charge per unit length of material.

Data:

The metal cylinder is hollow.

The unit length is L.

a.The expression will be as follows:

for charge inside the cylinder, where r < R, the expression is:

E = \frac{\lambda }{(2\epsilon * r) }

b. Let's assume that the cylinder is a coaxial cylinder with a radius r > R, then the electrical field strength is given as:

E = \frac{Q ( enclosed)}{A*\epsilon }

E = \frac{\lambda*L+2(\lambda)*L }{(A)*\epsilon(outside) }

E  = \frac{3(\lambda)L }{(2\pi*R*L*\epsilon(outside)  }

This gives:

E = \frac{3(lambda)}{2\pi*\epsilon(outside)  }

The solution informs us that there is a surface change taking place on the cylinder. Therefore, there will not be a magnetic field across it.

3 0
4 years ago
10 PTS.
gayaneshka [121]

1.2 x (2.2 x 10⁵) = 264,000 Ω

0.8 x (2.2 x 10⁵) = 176,000 Ω

With a 'nominal' value of 220,000 Ω, it could actually be anywhere <em>between 176,000Ω and 264,000Ω</em> .

8 0
3 years ago
Earth is the only source of gravity in the solar system. Do you agree?
PolarNik [594]
I strongly disagree. There are many other planets in our solar system that have gravity on them. The statement is false. I hope this helps.
3 0
3 years ago
Read 2 more answers
A box is moved 10 m across a smooth floor by a force F making a downward angle with the floor, so that there is effectively a 4
Brut [27]

Answer:

Zero

Explanation:

Impulse is defined as the change in momentum.

Impulse is also defined as the product of force and the time duration of application of the force.

In the given problem, since there is no motion in the vertical direction, therefore the velocity of the box along the vertical direction is zero. So, momentum of the box along the vertical is also zero.

Hence the change is momentum is also zero along vertical direction.

Thus the impulse delivered by the box is zero.

6 0
3 years ago
A rubber band has a spring constant of 75 N/m. How much force is required to stretch the rubber band 0.02 m past its natural len
ale4655 [162]

Answer:

(75 x 0.02) = 1.5 N

Explanation:

7 0
3 years ago
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