9.3 x 10⁻⁶N
Explanation:
Given parameters:
Mass 1 = 70kg
Mass 2 = 2000kg
distance = 1m
Unknown:
force between them =
Solution:
The force between the two masses will be a gravitational force of attraction.
F = 
G is universal gravitation constant = 6.67430×10−¹¹ N⋅m²/kg²
r is the distance between the two masses
Substituting the parameters:
F = 
= 9.3 x 10⁻⁶N
Learn more:
Universal gravitation constant
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Answer:
where is volume? formula of density is: mass/volume so volume must be there
Weight = (mass) x (acceleration of gravity at the place where the mass is) .
Man's mass = 80 kg
His weight on Earth = (80 kg) x (9.8 m/s²) = 784 newtons (about 176 pounds)
His weight on the Moon = (80 kg) x (1.63 m/s²) = <em>130.4 newtons</em> (about 29.2 pounds)
His mass is <em>80 kg</em>. Mass is the thing about him that doesn't change.
He has the same mass on the Earth, on the Moon, or anywhere.
Answer:
D- component of the gravitational force parallel to the plane increased and normal force exerted by the board decreased
Explanation:
component of the gravitational force parallel to the plane = mg sinθ ; where θ is inclination of the plane . As it increases , sinθ increases and hence component of the gravitational force parallel to the plane increases .
normal force exerted by the board = mg cosθ . As θ increases , cosθ decreases and hence normal force exerted by the board decreases and hence friction force decreases because
Friction force = coefficient of friction x normal force exerted by the board .
coefficient of friction remains constant.
Answer:
0.610m/s^2
Explanation:
Acceleration is defined as the ΔV/ΔT. In this case, the change in velocity is 1.43-0.32=1.11 m/s. The change in time is 1.82 seconds. Plugging in what we know, it will result in an acceleration of 0.610 m/s^2.
