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3 years ago

Which statement best compares an asteroid with Earth?

Physics

2 answers:

Rina8888 [55]3 years ago

6 0

Answer:

c. both have rocky composition

Explanation:

Alla [95]3 years ago

4 0

Answer:

C) Both have rocky composition

Explanation

Earth has rocks. Many many rocks.

It is made of many type of rocks such as sedimentary, metamorphic, and igneous rocks. and guess what a asteroid is? That is right ! A ROCK.
A asteroid is normally made of stony silicate rocks , but not always , sometimes I can be diamonds!! The point is , they both are rocks floating around space.

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Peter, a 100 kg basketball player, lands on his feet after completing a slam dunk and then immediately jump up again to celebrat

Ludmilka [50]

Answer:

1800 N

Solution:

Impulse = mΔv = m * (u - v) .

here m = 100 kg

u = 4 m/s

v = -5 m/s

impulse = 100 x ( 4 - ( -5 ) ) = 900 Kg m/s .

Average reaction Force ( Favg ) = impulse / Δt

Average reaction Force ( Favg ) = 900kg·m/s / 0.5s

Average reaction Force ( Favg ) = 1800 N

6 0

3 years ago

A car with a mass of 600 kg is traveling at a velocity of 10 m/s. How much kinetic energy does it have?

vaieri [72.5K]

Answer:

30000 J = 30 kJ

Explanation:

Kinetic energy is the energy possessed by a moving object solely due to its motion.

You can get the K.E. of an object using the equation,

K.E. = $\frac{1}{2} mv^{2}$

So you get,

K.E. = $\frac{1}{2} 600×10^{2}$

= 30000 J = 30 kJ

3 0

3 years ago

A driver drives for 30.0 minutes at 80.0 km/h, then 45.0 minutes at 100 km/h. She then stops 30 minutes for lunch. She then trav

bija089 [108]

Answer:

b) 68,9 km/h a) picture

Explanation:

In this problem, since velocity is expressed in km/h and time in minutes, we have to convert either time to hours or velocity to km/min. It is easier to use hours.

Using this formula we pass time to hours:

$t_{hours}=t_{min}*\frac{1 h}{60 min}\\30min*\frac{1 h}{60 min}=0,5h\\45min*\frac{1 h}{60 min}=0,75h$

Now we can plot speed vs time (image 1). The problem says that the driver uses constant speed, so all lines have to be horizontal.

Using the values of the speed we calculate the distance in each interval

$d=v*t\\80km/h*0.5h=40km\\100km/h*0.75h=75km$

Using these values and the fact that she was having lunch in the third one (therefore stayed in the same position), we plot position vs time, using initial position zero (image 2, distance is in km, not meters).

Finally, we compute the average speed with the distance over time:

$v_{average}=\frac{155km}{2.25h}=68.9km/h$