The question mentions a change in temperature from 25 to 50 °C. With that, the aim of the question is to determine the change in volume based on that change in temperature. Therefore this question is based on Gay- Lussac's Gas Law which notes that an increase in temperature, causes an increase in pressure since the two are directly proportional (once volume remains constant). Thus Gay-Lussac's Equation can be used to solve for the answer.
Boyle's Equation:

=

Since the initial temperature (T₁) is 25 C, the final temperature is 50 C (T₂) and the initial pressure (P₁) is 103 kPa, then we can substitute these into the equation to find the final pressure (P₂).

=

∴ by substituting the known values, ⇒ (103 kPa) ÷ (25 °C) = (P₂) ÷ (50 °C)
⇒ P₂ = (4.12 kPa · °C) (50 °C)
=
206 kPa
Thus the pressure of the gas since the temperature was raised from 25 °C to 50 °C is
206 kPa
Explanation:
Relation between length of a curve and angle is as follows.
l = 
where, R = radius of curve
= angle in radians
Also, l =
.......... (1)
If curve has a degree of curvature
for standard length s, then
R =
........... (2)
Now, substitute the value of R from equation (2) into equation (1) as follows.
l =
If s = 30 m, then calculate the value of l as follows.
l =
=
= 452 m
thus, we can conclude that the length of the curve is 452 m.
A cl2 molecule is a diatomic molecule composed of two atoms of identical halogen - chlorine. In this case, this molecule is composed of covalent bonds in which the identical atom- molecule tells that this is also non-polar. To break the bond, energy has to be absorbed to break the intermolecular force that bound the molecule together.
The answers are :
1 - F
2- T
Answer:
d = 0.9 g/L
Explanation:
Given data:
Number of moles = 1 mol
Volume = 24.2 L
Temperature = 298 K
Pressure = 101.3 Kpa (101.3/101 = 1 atm)
Density of sample = ?
Solution:
PV = nRT (1)
n = number of moles
number of moles = mass/molar mass
n = m/M
Now we will put the n= m/M in equation 1.
PV = m/M RT (2)
d = m/v
PM = m/v RT ( by rearranging the equation 2)
PM = dRT
d = PM/RT
The molar mass of neon is = 20.1798 g/mol
d = 1 atm × 20.1798 g/mol / 0.0821 atm. L/mol.K × 273K
d = 20.1798 g/22.413 L
d = 0.9 g/L