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3 years ago

Which of the following statements is not accurate in regard to the first four energy levels?

Chemistry

1 answer:

seropon [69]3 years ago

3 0

Answer:

D) False

Explanation:

A) True

The third energy level with principal quantum number n =3 will have s,p,d orbitals where the s, p ,d orbitals can accommodate a maximum of 2,6 and 8 electrons respectively. Therefore, total electron count = 18

B) True

The fourth energy level corresponds to n = 4 with s,p,d and f orbitals

C) True

A given orbital can accommodate a maximum of 2 electrons, one in the spin up and the other in a spin down orientation

D) False

The first energy level has n =1 with only s orbital

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How many moles of carbon dioxide are produced from 8.73 moles of tristearin?

matrenka [14]

Answer:

Explanation:

8.73 mol x mol

2 C57H110O6(S) + 163 O2(g) ---> 114 CO2(g) + 110 H2O(I)

2 mol 114 mol

8.78 mol (114mol/2 mol) =500.46 mol

8 0

3 years ago

A sample of water is heated from 60.0 °C to 75.0°C by the addition of 140 j of

kupik [55]

Mass of the water : 2.23 g

<h3>Furter explanation</h3>

Heat

Q = m.c.Δt

m= mass, g

c = heat capacity, for water : 4.18 J/g° C.

ΔT = temperature

Q= 140 J

Δt = 75 - 60 = 15

mass of the water :

$\tt m=\dfrac{Q}{c.\Delta T}=\dfrac{140}{4.18\times 15}=2.23~g$

5 0

3 years ago

Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm

8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

$\frac{dV}{dt}=10\frac{cm^3}{s}$

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

$\frac{dh}{dt} = ?*\frac{dV}{dt}$

Of course, $?=\frac{dh}{dV}$ .

Now, since the volume of a cone is $V=\pi r^2h/3$ and the ratio $r/h=15/20=3/4$ or $r=3/4h$ , the volume becomes:

$V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3$

We proceed to its differentiation:

$\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}$

Then, we compute $\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}$

Finally, at h=2:

$\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}$

Best regards.

4 0

3 years ago

Other than providing vital oxygen, how else do plants support us, especially considering our diet of plants and animals (which c

arsen [322]

Plants serve as the main source of nutrition for humans as well as provide many products for human use, such as firewood, timber, fibers, medicines, dyes, oils, and rubber.

Plants are multicellular eukaryotic organisms whose mode of nutrition is mainly autotrophic.

Plants play many important roles in life more especially that of producing food on which many other organisms depend on.

Some of the important ways by which plants support human life include:

Provision of food: plants trap the energy of the sunlight and through the process of photosynthesis produce food on which other living organisms such as animals depend on.
Provision of oxygen: during the process of photosynthesis, plant release oxygen into the atmosphere which is needed by animals for respiration.
Recycling of water: through the process of transpiration occurring in leaves of plants, water is recycled in nature.
Provision of other products such as timber, fibers, medicines, dyes, oils, and rubber.

Therefore, plants serve as the main source of nutrition for humans as well as provide many products for human use, such as timber, fibers, medicines, dyes, oils, and rubber.

Learn more about importance of plants at: https://brainly.in/question/237715

8 0

3 years ago

A 50 gram sample of a radioisotope undergoes 2 half-lives. How many grams

Veseljchak [2.6K]

Answer:

At the end of second half life 12.5 g will left

Explanation:

Given data:

Total Mass = 50 g

Half lives = 2

Mass remain at the end = ?

Solution:

At time zero = 50 g

At 1st half life = 50 g /2 = 25 g

At second half life = 25 g/2 = 12.5 g

So at the end of second half life 12.5 g will left.

3 0

3 years ago