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7nadin3 [17]
3 years ago
13

A bird watcher spots a sparrow in a tree. The sparrow sits in a nest that is 10.5 feet above the bird watcher's eye level, at a

35° angle of elevation from the bird watcher. The bird watcher then notices a hawk in the same tree, 7.4 feet above the sparrow, at a certain angle of elevation. The bird watcher stands 15 feet from the base of the tree. What is the angle of elevation from the bird watcher to the hawk?
Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

the angle is 50 degrees.

Explanation:

To solve this trigonometric problem we need ot remember that:

\alpha=arctg(\frac{O}{A})

where O is the opposite side of the triangle and A the adjacent

The hawk is 7.4 feet above the sparrow so:

O=10.5+7.4\\O=17.9ft

\alpha =arctg(\frac{17.9}{15})=50^o

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A Safety Data Sheet (SDS) provides even more information on chemicals than a label: True.

<h3>What is a Safety Data Sheet (SDS)?</h3>

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What is paleomagnetism how has it been used to understand plate tectonics?
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In an "atom smasher," two particles collide head on at relativistic speeds. If the velocity of the first particle is 0.741c to t
galina1969 [7]

Answer:

W_x = 0.9156\ c

Explanation:

given,

velocity of particle 1 = 0.741 c to left

velocity of second particle = 0.543 c to right

relative velocity between the particle = ?

for the relative velocity calculation we have formula

W_x = \dfrac{|u_x - v_x|}{1-\dfrac{u_xv_x}{c^2}}

u_x = 0.543 c

v_x = - 0.741 c

W_x = \dfrac{0.543 c - (-0.741 c)}{1-\dfrac{(0.543 c)(-0.741 c)}{c^2}}

W_x = \dfrac{0.543 c +0.741 c)}{1+\dfrac{(0.543)(0.741)c^2}{c^2}}

W_x = \dfrac{1.284c}{1+0.402363}

W_x = 0.9156\ c

Relative velocity of the particle is W_x = 0.9156\ c

5 0
3 years ago
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