Ask question

Ask question

All categories

3 years ago

13

A bird watcher spots a sparrow in a tree. The sparrow sits in a nest that is 10.5 feet above the bird watcher's eye level, at a

35° angle of elevation from the bird watcher. The bird watcher then notices a hawk in the same tree, 7.4 feet above the sparrow, at a certain angle of elevation. The bird watcher stands 15 feet from the base of the tree. What is the angle of elevation from the bird watcher to the hawk?

1 answer:

11Alexandr11 [23.1K]3 years ago

6 0

Answer:

the angle is 50 degrees.

Explanation:

To solve this trigonometric problem we need ot remember that:

$\alpha=arctg(\frac{O}{A})$

where O is the opposite side of the triangle and A the adjacent

The hawk is 7.4 feet above the sparrow so:

$O=10.5+7.4\\O=17.9ft$

$\alpha =arctg(\frac{17.9}{15})=50^o$

You might be interested in

What is the function (job) of the genes in protein synthesis (how proteins are made in the cell)?

Alborosie

Answer:Most genes contain the information needed to make functional molecules called proteins. (A few genes produce regulatory molecules that help the cell assemble proteins.) The journey from gene to protein is complex and tightly controlled within each cell. It consists of two major steps: transcription and translation.

Explanation:

5 0

2 years ago

A student wants to approximate the amount of work that the force due to gravity does on the student as the student walks up a se

Inessa [10]

Answer:

Options A and D

Explanation:

In this question the student needs to collect these measurements in order to approximate the work done

A. The mass of the student

D. The final vertical height above the initial vertical position.

Workdone = mgh

m = mass

g = gravity = 9.8m/s²

h = vertical height between the initial and the final positions.

The vertical height has to be known as gravity only acts straight down.

3 0

3 years ago

A 9.6 cm diameter circular loop of wire is in a 1.10 T magnetic field perpendicular to the plane of the loop. The loop is remove

Natali5045456 [20]

Answer:

Thus induced emf is 0.0531 V

Solution:

As per the question:

Diameter of the loop, $d = 9.6\ cm = 0.096\ m$

Thus the radius of the loop, R = 0.048 m

Time in which the loop is removed, t = 0.15 s

Magnetic field, B = 1.10 T

Now,

The average induced emf, e is given by Lenz Law:

$e = - \frac{\Delta \phi_{B}}{\Delta t}$

$e = - \frac{\Delta \phi_{B}}{\Delta t}$

where

$\phi_{B}$ = magnetic flux = $A\Delta B$

where

A = cross sectional area

Also, we know that:

$e = - \frac{A\Delta B}{\Delta t}$

$e = - \frac{\pi r^{2}\times (0 - 1.10)}{0.15}$

$e = - \frac{\pi \times 0.048^{2}\times (0 - 1.10)}{0.15}$

e = 0.0531 V

The sketch is shown in the figure, where I indicates the direction of the induced current.

3 0

3 years ago

Read 2 more answers

What are the components of a vector with a magnitude of 4.00 and a direction of -112°?

zzz [600]

Answer: (-1.50 -3.71)

Explanation:

4 0

3 years ago

A net force of 1.6×10−15 N acts on an electron over a displacement of 5.0 cm, in the same direction as the net force. (a) What i

Margaret [11]

Explanation:

It is given that,

Net force acting on the electron, $F=1.6\times 10^{-15}\ N$

Displacement, d = 5 cm = 0.05 m

(a) Let $\Delta E$ is the change in kinetic energy of the electron. It can be calculated using work energy theorem. Mathematically, it is given by :

$W=\Delta E$

$\Delta E=F\times d$

$\Delta E=1.6\times 10^{-15}\ N\times 0.05\ m$

$\Delta E=8\times 10^{-17}\ J$

(b) Initial speed of the electron, u = 0

Again using the work energy theorem as :

$E=\dfrac{1}{2}m(v^2-u^2)$

$E=\dfrac{1}{2}m(v^2)$

$v=\sqrt{\dfrac{2E}{m}}$

$v=\sqrt{\dfrac{2\times 8\times 10^{-17}}{9.1\times 10^{-31}}}$

$v=1.32\times 10^7\ m/s$

Hence, this is the required solution.

7 0

3 years ago