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Dmitrij [34]
3 years ago
5

A 0.450kg soccer ball has a kinetic energy off 199j. Calculate the velocity of the soccer ball

Physics
1 answer:
disa [49]3 years ago
6 0

Answer:

v = 29.73[m/s]

Explanation:

Kinetic energy is defined by the following equation:

E_{k}=\frac{1}{2}*m*v^2 \\199=0.5*0.45}*v^2\\v=\sqrt{\frac{199}{0.5*0.45} }\\ v= 29.73[m/s]

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Answer:

"13.48 Kwhr" is the right solution.

Explanation:

The given values are:

Average rate of heat energy,

= 0.063 W/m²

Diameter,

= 8m

Efficiency of conversion,

= 50%

Now,

The area of hotspot will be:

⇒  A=\frac{\pi}{4} d^2

On substituting the values, we get

⇒      =\frac{3.14}{4} (8)^2

⇒      =0.785\times 64

⇒      =50.24 \ m^2

Total heat generation rate will be:

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        =0.063\times 50.24

        =3.16 \ W

hence,

The electricity generation capacity will be:

⇒  P=\eta Q t

On substituting the values, we get

⇒      =0.5\times 3.16\times 8760

⇒      =13840.8 \ Whr

On converting into Kwhr, we get

⇒      =13.84 \ Kwhr

6 0
3 years ago
When you catch a baseball, what kind of work do you do, negative or positive? By catching the baseball, what do you change? Does
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A vertically polarized beam of light of intensity 100 W/m2 passes through two ideal polarizers. The transmission axis of the fir
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To solve the problem it is necessary to apply the Malus Law. Malus's law indicates that the intensity of a linearly polarized beam of light, which passes through a perfect analyzer with a vertical optical axis is equivalent to:

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Where,

I_ {0} indicates the intensity of the light before passing through the polarizer,

I is the resulting intensity, and

\theta indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

Since we have two objects the law would be,

I=I_0cos^2\theta_1*cos^2(\theta_2-\theta_1)

Replacing the values,

I=100*cos^2(20)*cos^2(40-20)

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