Answer:
The magnitude of the acceleration of the tip of the minute hand of the clock 
.
Explanation:
Given that,
Length of minute hand = 0.55 m
Length of hour hand = 0.26 m
The time taken by the minute hand to complete one revelation is
We need to calculate the angular frequency
Using formula of angular frequency
Put the value into the formula
We need to calculate the magnitude of the acceleration of the tip of the minute hand of the clock
Using formula of acceleration
Put the value into the formula
Hence, The magnitude of the acceleration of the tip of the minute hand of the clock .
Answer:
979.6 kg/m³
Explanation:
We know pressure P = hρg where h = height of liquid = 10.5 m, ρ = density of liquid and g = acceleration due to gravity = 9.8 m/s²
So, density ρ = P/hg
Since P = 100.8 kPa = 100.8 × 10³ Pa
substituting the values of the variables into the equation for ρ, we have
ρ = P/hg
= 100.8 × 10³ Pa ÷ (10.5 m × 9.8 m/s²)
= 100.8 × 10³ Pa ÷ 102.9 m²/s²
= 0.9796 × 10³ kg/m³
= 979.6 kg/m³
So, the density of the liquid is 979.6 kg/m³
Answer:
T
Explanation:
= Power of the bulb = 100 W
= distance from the bulb = 2.5 m
= Intensity of light at the location
Intensity of the light at the location is given as
= 1.28 W/m²
= maximum magnetic field
Intensity is given as
T
