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Ilya [14]
3 years ago
6

Explain why the quantum number set (3, 2, 3, -½) is not possible for an electron in an atom.

Chemistry
1 answer:
Doss [256]3 years ago
5 0
I think because there is no such quantum shell as -1/2. 
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Butanoic acid + 2 propanol
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Butanoic acid and 2-propanol reacts to form isopropyl butyrate.

Explanation:

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When an ionic solid is added into a solvent, you can see that the ionic solid dissociates into its respective cations and anions
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The order of the steps, from first to last, is as follows based on the information in the question:

1. Salt is broken down into cations and anions.

2. Anion hydration.

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4. Cations and anions that have been dissolved start to settle as a solid salt.

5. The rate of dissolution and recrystallization are equal.

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4 0
2 years ago
What are giant piles of mining waste called?
weqwewe [10]
The giant piles of mining waste called tailings. These wastes consists of ground rock and process effluents from a mining plant. These wastes are stored on a surface either in a facility or in the form of piles. Also, sometimes it is stored underground in areas that are mined out.
3 0
3 years ago
Read 2 more answers
Given the following formula for calculating the ionization energy of one-electron species such as Li2+, He+, and H, calculate th
Yuki888 [10]

Answer:

The answer is "32819.9 \ \frac{J}{mol}\\\\"

Explanation:

Boron: 5^{B}\to 1s^2 2s^2 2p^1

\Delta E=-2.18\times 10^{-18}\ \frac{J}{atom}\ (\frac{1}{\infity^2}-\frac{1}{n^2_{initial}})(z^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\

      =-2.18\times 10^{-18}\ \frac{J}{atom}\ (0-\frac{1}{1})(5^2) (6.022\times 10^{23}\ \frac{atom}{mol})\\\\ =2.18\times 10^{-18}\times 25 \times 6.022\times 10^{23}\ (\frac{J}{mol})\\\\ =328.199 \times 10^{5}\ (\frac{J}{mol})\\\\ =32819 \times 10^{3}\ (\frac{J}{mol})\\\\ =32819.9 \ (\frac{J}{mol})\\\\

4 0
3 years ago
Magnesium has three naturally occurring isotopes with masses of 23.99, 24.99, and 25.98 amu and natural abundances of 78.99%, 10
Elodia [21]

Answer:

24.309

Explanation:

Let A, B, and C represent the three isotopes.

For isotope A:

Mass number = 23.99

Abundance = 78.99%

For isotope B:

Mass number = 24.99

Abundance = 10.00%

For isotope C:

Mass number = 25.98

Abundance = 11.01%

Atomic mass of Mg =?

Atomic mass = [(Mass of AxA%)/100] + [(Mass of BxB%)/100] + [(Mass of CxC%)/100]

Atomic Mass = [(23.99x78.99)/100] + [(24.99x 10)/100] + [(25.98x11.01)/100]

Atomic number = 18.950 + 2.499 + 2.860

Atomic mass of Mg = 24.309

3 0
3 years ago
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