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Ilya [14]
3 years ago
6

Explain why the quantum number set (3, 2, 3, -½) is not possible for an electron in an atom.

Chemistry
1 answer:
Doss [256]3 years ago
5 0
I think because there is no such quantum shell as -1/2. 
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The atomic number of sodium (Na) is 11. This is also the number of which of the following?
attashe74 [19]
D. Protons, Atomic number is the number of protons in an atom.
3 0
3 years ago
Vinegar is a solution of acetic acid (the solute) in water (the solvent) with a solution density of 1010 g/L. If vinegar is 0.80
Damm [24]

Answer:

4.8 %

Explanation:

We are asked the concentration in % by mass, given the molarity of the solution and its density.

0.8 molar solution means that we have 0.80 moles of acetic acid in 1 liter of solution. If we convert the moles of acetic acid to grams, and the 1 liter solution to grams, since we are given the density of solution, we will have the values necessary to calculate the % by mass:

MW acetic acid = 60.0 g/mol

mass acetic acid (the solute) = 0.80 mol x 60 g / mol = 48.00 g

mass of solution = 1000 cm³ x 1.010 g/ cm³      (1l= 1000 cm³)

                            = 1010 g

% (by mass) = 48.00 g/ 1010 g  x 100 = 4.8 %

6 0
3 years ago
How many atoms of hydrogen are in 0.500 mol of ch3oh molecules?
cestrela7 [59]
In 1 mol of CH3OH, you have 4 H-atoms (because 3 H-atoms are attached to the C-atom, and one H-atom in the OH group). That means in 0.500 mol of CH3OH, you have 2 H-atoms since it is halved. And then we have Avogadro's constant: 6.02 * 1023.

The question asks for how many hydrogen atoms there are in 0.500 mol CH3OH. Using the numbers that we have (Avogadro's constant and no. of H-atoms), the answer of the question will be something like:

<span>H-atoms in CH3OH = 2 * 6.02 * </span>1023<span> = ~1.2 * 10</span>24

 


8 0
3 years ago
21. What is the frequency, given 2-3 x 10¹m? Show all work
Aloiza [94]

Answer:

Frequency is 2Hz

Explanation:

5 0
1 year ago
Is KNO a strong acid?
stira [4]

Answer:

First of all, it's KNO₃ not KNO.

Second, KNO₃ is neither an acid nor it is a base, infact, it is a salt and therefore it's neutral.

hope that helps...

3 0
3 years ago
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