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erastova [34]
4 years ago
15

The water tower shown below has a spherical reservoir (outlined in black) with measured diameter of 25.0 m. The reservoir is fil

led to 80.0% of its full capacity.
Smith house
Use the correct number of significant figures to indicate the volume of water in the spherical reservoir.
Physics
1 answer:
OlgaM077 [116]4 years ago
8 0

Answer:

6,540m³ (or 6.50×10⁶ L)

Explanation:

  • Volume of a Sphere = (4/3)πr³
  • 80% of a quantity = [quantity]•(0.8)

The volume of that sphere at 80% capacity is:

[(4/3)π(12.5m)³]•(0.8)= 6,544.98...m³

I may be wrong about the sig-figs, but I believe it is 3 due to the 12.5m... so I'm rounding it to tens place to get the answer above.

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Identify the scale of measurement used.
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The left plate of a parallel plate capacitor carries a positive charge Q, and the right plate carries a negative charge -Q. The
True [87]

Answer:

Explanation:

Capacitance of capacitor

= ε₀ A / d , ε₀ is permittivity of space , A is area of plate , d is distance between plates.

= 8.85 x 10⁻¹² x 2 x 10⁻³ / (6 x 10⁻³)

= 2.95 x 10⁻¹² F

Electric field E = V / d , V is potential difference

V = E x d

= 100 x 10³ x 6 x 10⁻³

= 600 V

Charge on the capacitor

= capacitance x potential difference

= 2.95 x 10⁻¹² x 600

= 17.7 x 10¹⁰ C

3 0
3 years ago
A 2.00-m long uniform beam has a mass of 4.00 kg. The beam rests on a fulcrum that is 1.20 m from its left end. In order for the
Shalnov [3]

Answer:

x ’= 1,735 m,  measured from the far left

Explanation:

For the system to be in equilibrium, the law of rotational equilibrium must be fulfilled.

Let's fix a reference system located at the point of rotation and that the anticlockwise rotations have been positive

             

They tell us that we have a mass (m1) on the left side and another mass (M2) on the right side,

the mass that is at the left end x = 1.2 m measured from the pivot point, the mass of the right side is at a distance x and the weight of the body that is located at the geometric center of the bar

           x_{cm} = 1.2 -1

          x_ {cm} = 0.2 m

          Σ τ = 0

          w₁ 1.2 + mg 0.2 - W₂ x = 0

          x = \frac{m_1 g\ 1.2 \ + m g \ 0.2}{M_2 g}

          x = \frac{m_1 \ 1.2 \ + m \ 0.2 }{M_2}

let's calculate

          x = \frac{2.9 \ 1.2 \ + 4 \ 0.2 }{8.00}2.9 1.2 + 4 0.2 / 8

           

          x = 0.535 m

measured from the pivot point

measured from the far left is

           x’= 1,2 + x

           x'=  1.2 + 0.535

           x ’= 1,735 m

8 0
3 years ago
Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.0
e-lub [12.9K]

Answer:

f = 421.8 Hz

Explanation:

When she moved a distance of 1 m from mid point she observe first destructive interference due to two speakers

so we can say that path difference of sound due to two speakers will be equal to half of the wavelength

so path difference is given as

\Delta L = {3.5^2 + 12^2}^{0.5} - {1.5^2 + 12^2}^{0.5}

so it will be

\Delta L = 12.5 - 12.093

\Delta L = 0.4066

now we know that

\frac{\lambda}{2} = 0.4066

\lambda = 0.813

now frequency of sound is given as

f = \frac{v}{\lambda}

f = \frac{343}{0.813}

f = 421.8 Hz

4 0
3 years ago
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