Given: Work W = 44 J; Mass of the rope and the bucket m= 1.5 Kg
Required: Find the height in meters
Formula: Work = Force x distance but Force = Weight = mg g = 9.8 m/s²
W =Fd W = mgh h = W/mg
h = 44 J/(1.5 Kg)(9.8 m/s²)
h = 2.99 m or 3 m
Answer:x=79,202.77 ft
Explanation:
Given
plane is at a height of 32000 ft
angle of depression is
let x the distance between the point directly below the plane and airport be x
from diagram
x=79,202.77 ft
distance between plane and airport
h=85,422.94 ft
Answer:
2.40 x 10⁻¹³ C
Explanation:
= number of electrons = 6.25 x 10⁶
= charge on electron = - 1.6 x 10⁻¹⁹ C
= number of protons = 7.75 x 10⁶
= charge on proton = 1.6 x 10⁻¹⁹ C
Net charge is given as
Q = +
Q = (- 1.6 x 10⁻¹⁹) (6.25 x 10⁶) + (1.6 x 10⁻¹⁹) (7.75 x 10⁶)
Q = 2.40 x 10⁻¹³ C
Answer:
Which item fits in the left side of the table?Criminal versus Civil Cases Criminal cases Civil cases ? . • Accuser is called the plaintiff • Lower burden of proof Defendant may be found liable • Usually heard by a judge only • Accused not guaranteed an attorney
A. No burden of proof
B. Accuser is called the defendant
C. Defendant may be found guilty
D. Usually heard by a jury only
The constant force applied to the rope is 7.72 N.
<h3>Net torque on the drum</h3>
The net torque on the drum is calculated as follows;
Linear speed, v = ωr = 23 x 0.4 = 9.2 m/s
distance traveled = 14 m
<h3>Tangential acceleration</h3>
The acceleration of the drum is calculated as follows;
v² = u² + 2as
v² = 0 + 2as
v² = 2as
a = v²/2s
a = (9.2)/2(14)
a = 0.329 m/s²
<h3>Angular acceleration of the drum</h3>
<h3>Applied force</h3>
The constant force applied to the rope is calculated as follows;
Learn more about net torque here: brainly.com/question/15262027