Typically a scaffolding has two ropes to support it. One
on the left most side while the other one is on the right most side. Based on
equilibrium rule, the summation of forces must be 0. The downward force is the
weight of person and scaffolding, while the upward force are the tensions on
the two ropes, hence:
Weight person + Weight scaffolding = 2 * Tension
500 N + Weight scaffolding = 2 * 400 N
Weight scaffolding = 300 N
Answer:
C) The restoring force
Explanation:
Hooke's Law states that the restoring force acting on a spring is given by the equation:
where
k is the spring constant
x is the displacement of the spring from its equilibrium position
The negative sign in the equation tells the direction of the restoring force. In fact, this force tends to bring the spring back to its equilibrium position: so, the force is always in opposite direction to the displacement.
This means that when the spring is stretched to the right, the restoring force tends to bring it back to the left, to the equibrium position; if the spring is compressed to the left, the restoring force tends to bring it back to the right, to the equilibrium position.
So the correct option is
C) The restoring force
Answer: B
F = 2.4 N
Explanation: Given that
Magnetic field B = 0.60 T
Current I = 5 A
Length L = 0.8 m
The force on an individual charge moving at the drift velocity Vd is given by F = qVdB sin θ.
Since current = charge/time
I = q/t
q = It
Also, recall that V = L/t. Therefore
F = I × t × L/t × B × sinØ
F = ILBsin θ
Since the wire is at right angles to the magnetic field
Sin θ = sin 90 = 1 then,
F = 5 × 0.8 × 0.6 = 2.4N
The force on the wire is 2.4 N
Answer:b-right
Explanation:
Given
current is flowing into the screen i.e. direction
length of wire is also in direction
Force experienced is in negative y direction i.e.
Force experienced by a current carrying wire in a magnetic field experience a force is given by
where I=current
L=length of element
B=magnetic field
Direction of magnetic field must be in
as