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kompoz [17]
3 years ago
13

You place a balloon in a closed chamber at standard temperature and pressure (STP). You cool the chamber to half of its original

temperature while leaving the pressure constant. What happens to the balloon?
It stays the same volume.

It decreases to one-half of its original volume.

It doubles in volume.

It expands to four times its original volume.
Chemistry
2 answers:
Goryan [66]3 years ago
7 0
It decreases to one half of its original volume.
AnnyKZ [126]3 years ago
6 0
I think the correct answer from the choices listed above is the second option. At constant temperature, the volume of the system at the new conditions will decrease to <span>one-half of its original volume.

V1 = nRT1 / P


V2 = nRT1 / 2P = 2V1</span>
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Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

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