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kompoz [17]
3 years ago
13

You place a balloon in a closed chamber at standard temperature and pressure (STP). You cool the chamber to half of its original

temperature while leaving the pressure constant. What happens to the balloon?
It stays the same volume.

It decreases to one-half of its original volume.

It doubles in volume.

It expands to four times its original volume.
Chemistry
2 answers:
Goryan [66]3 years ago
7 0
It decreases to one half of its original volume.
AnnyKZ [126]3 years ago
6 0
I think the correct answer from the choices listed above is the second option. At constant temperature, the volume of the system at the new conditions will decrease to <span>one-half of its original volume.

V1 = nRT1 / P


V2 = nRT1 / 2P = 2V1</span>
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Answer: C) Roman numeral following the name.

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Now, if we have something like FeCl_3 and we write the name as Iron chloride, then it will not be correct since Fe is a transition metal and it shows +2 and +3 oxidation states. So, to overcome this difficulty, a roman numeral is used for the oxidation state of the metal ion. The name of above compound will be Iron(III)chloride. Similarly, if we have FeCl_2 then its name will be written as Iron(II)chloride.

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when naming a transition metal ion that can have more than one common ionic charge, the numerical value of the charge can be indicated by a Roman numeral following the name.

8 0
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