Answer:
t = 123.59s
Explanation:
For the launch pad section:
Vf = Vo + a*t where Vo=0.
Vf = 35*25 = 875m/s
The distance traveled during the launch:
Now the projectile motion, we know that its initial speed is the speed calculated previously and the initial height is the y-component of the previously calculated distance.
where d= 10937.5m; Vo=875m/s.
Solving for t:
t1 = -11.093s t2 = 98.59s
So, the total time of flight will be:
Answer: a, c, and g
Explanation:
Buoyant Force is an upward force acting on submerged object equal to weight of fluid displaced by the submerged object.
If no part is submerged (V = 0) that is volume. Therefore there is Zero Buoyant Force.
Fully submerged produces greatest buoyant force since greatest amount of fluid was displaced.
Whenever it is fully submerged it will have the greatest buoyant force.
Buoyant Force DOES NOT Depend on Depth
A fully submerged object displaces its volume in fluid
A floating object displaces its weight in fluid.
In a solution, a SOLUTE is the substance being dissolved.
In a solution, a SOLVENT is the substance in which something is dissolved.
For example in salt water, the salt is the solute. And the water is the solvent. Usually, which substance has a larger amount in the solution can be called a solvent. It doesn't matter if it's a gas, solid, or liquid. They can all be solute or solvents.
Answer:
The minimum wall thickness required for the spherical tank is 0.0189 m
Explanation:
Given data:
d = inside diameter = 8.1 m
P = internal pressure = 1.26 MPa
σ = 270 MPa
factor of safety = 2
Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?
The allow factor of safety:
The minimun wall thickness:
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s
