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3 years ago

A 1.5m wire carries a 8A current when a potential difference of 67v is applied what is the resistance of the wire

Physics

1 answer:

Drupady [299]3 years ago

8 0

Data is inappropriate

here, we need gauge of the wire i.e., diameter of the wire, so that we calculate the resistance by using the formula

R = ρl/A

where R= resistance ; Ω

l = length of wire ; m

A = area of wire ; m²

ρ = resistivity ; Ω-m

But in general ohms law is

V = I R

R = V/I ;

but here we also calculate "R" from length of wire in which the current is flowing.

I hope it is helpful to you.

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places with continental climates typically have _______ summers and ________ winters warm; cool hot; cool warm; cold hot; cold

ipn [44]

Places with continental climates typically have hot summers and cold winters. As compared to places with mild climates, places with continental climates tend to experience the two extremes when it comes to the seasons. Summers can get very hot, and winters can get very cold.

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3 years ago

A 32-cm-long solenoid, 1.8 cm in diameter, is to produce a 0.30-T magnetic field at its center. If the maximum current is 4.5 A,

daser333 [38]

Answer:

<h2>16,931 turns</h2>

Explanation:

The magnetic field produced is expressed using the formula

$B = \frac{\mu_0NI}{L}$

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I is the current produced in the coil = 4.5A

$\mu_0$ is the magnetic permittivity in vacuum = 1.26*10^-6Tm/A

L is the length of the solenoid = 32 cm = 0.32 m

N is the number of turns in the solenoid.

Making N the subject of the formula from the equation above;

$B = \frac{\mu_0NI}{L}\\\\BL = \mu_0NI\\\\Dividing\ both\ sides \ by \ \mu_0I\\\\\frac{BL}{\mu_0I} =\frac{\mu_oNI}{\mu_0I} \\\\$

$N = \frac{BL}{\mu_0I}$

Substituting the give values to get N;

$N = \frac{0.3*0.32}{1.26*10^{-6} * 4.5}\\\\N = \frac{0.096}{0.00000567} \\\\N = 16,931.21$

The number of turns the solenoid must have is approximately 16,931 turns

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3 years ago

In what part of the scientific method do you record data?

densk [106]

C..............................

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2 years ago

A light ray traveling through a material with an index of refraction of 1.2 is incident on a material that has an index of refra

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Answer:

compared to the incident angle, the refracted angle is 45.56⁰

Explanation:

From Snell's law;

n₁sin(I) = n₂sin(r)

Where;

n₁ is the refractive index of light in medium 1 = 1.2

n₂ is the refractive index of light in medium 2 = 1.4

I is the incident angle

r is the refractive angle

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I = 56.439⁰

Applying snell's law

$n_1sin(I) = n_2sin(r)\\\\sin(r) = \frac{n_1sin(I) }{n_2}\\\\sin(r) = \frac{1.2*sin(56.439) }{1.4}\\\\sin(r) = 0.714\\\\r = sin^-(0.714)\\\\r = 45.56^o$

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