Answer:
9.9 ml of 0.200M NH₄OH(aq)
Explanation:
3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)
?ml of 0.200M NH₄OH(aq) reacts completely with 12ml of 0.550M FeCl₃(aq)
1 x Molarity NH₄OH x Volume Am-OH Solution(L) = 2 x Molarity FeCl₃ x Volume FeCl₃ Solution
1(0.200M)(Vol Am-OH Soln) = 3(0.550M)(0.012L)
=> Vol Am-OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liter = 9.9 milliliters
Explanation:
An element just has one-type atoms/atom (e.g. O2). Meanwhile, a compound is a variety of atoms (e.g. H2O).
Answer:The correct answer is option C.
Explanation:
At STP, 1 mol of gas occupies 22.4 L of volume
So, 100.0 L volume of 
will be occupied by :
According to reaction 2 moles are obtained from 1 mole of 
.
Then,4.4642 moles of will be obtained from :
that is 2.2321 moles of
Mass of gas:
Moles of gas Molar mass of gas:
Hence, the correct answer is option C.
Answer:
97.0%m/m es la concentración de la solución
Explanation:
El porcentaje masa/masa (%m/m) se define como 100 veces el radio entre la masa de soluto (300g de HCl) y la masa de la solución. Para hallar la masa de la solución debemos hallar la masa del agua (Solvente) haciendo uso de la ecuación del volumen de un cono. Con el volumen del cono podemos hallar la masa del agua haciendo uso de la densidad, así:
<em>Volumen:</em>
Volumen Cono = π*r²*h / 3
Donde r es el radio = 0.300m
h la altura = 5m
Volumen = π*(5m)²*0.300m / 3
7.85m³
<em>Masa Agua:</em>
7.85m³ * (1.2g / m³) = 9.42g Agua
<em>Masa solución:</em>
300g HCl + 9.42g Agua = 309.42g Solución
<em>%m/m:</em>
300g HCl / 309.42g * 100 =
<h3>97.0%m/m es la concentración de la solución</h3>
Answer:
The solid sugar crystals break apart in water as the sugar dissolves, but the individual sugar particles or molecules are still present and do not change as a result of dissolving in the water. The combined mass of the sugar and water shouldn't change.
Explanation:
