Technically speaking, yes you can. Using a microscope though.
For AlCl3 to be a Lewis acid, it would have to react in such a way that it accepted a lone pair from some other atom or molecule from a Lewis base.AlCl3 has an electron-deficient aluminum atom. It has only six electrons in its valence shell. It readily accepts electrons from other atoms, in an attempt to get a full valence shell of eight electrons.
Answer:
Atoms consist of three basic particles: protons, electrons, and neutrons. The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged).
The lowest smallest whole-number coefficient for H₂S is 5. Option C
<h3>What is the smallest whole-number coefficient for H₂S?</h3>
Now we know that a redox reaction is one in which there is a loss and gain of electrons One specie is oxidized (looses electrons) while another specie is reduced (gains electrons). The electrons must be transferred leading to an increase in oxidation number of one specie and a decrease in the oxidation number of another.
Now the reduction half equation is;
MnO4^-(aq) + 8H^+(aq) + 5e^- ----> Mn^2+(aq) + 4H2O (l)
The oxidation half equation is;
H2S(aq) ----> S^2-(aq) + 2H^+(aq) + 2e^-
Multiplying the reduction half equation by 2 and the oxidation half equation is 5
2MnO4^-(aq) + 16H^+(aq) + 10e^- ----> 2Mn^2+(aq) + 8H2O (l)
And;
5H2S(aq) ----> 5S^2-(aq) + 10H^+(aq) + 10e^-
The overall balanced reaction equation is;
2MnO4^-(aq) + 6H^+(aq) + 5H2S(aq) ----> 2Mn^2+(aq) + 8H2O (l) + 5S^2-(aq)
Thus the lowest smallest whole-number coefficient for H₂S is 5.
Learn more about redox reaction:brainly.com/question/13293425
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