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schepotkina [342]
4 years ago
8

A graph titled Position versus time for with horizontal axis time (seconds) and vertical axis position (meters). A straight blue

line runs with an upward slope from 0 seconds 3 meters to 4 seconds 15 meters. The starting position of this object is m. The object is traveling at a velocity of m/s.

Physics
2 answers:
eduard4 years ago
7 0

a) starting position of this object is 3m

b) Velocity is 3m/s

Explanation:

The points identified on the blue line are; (0,3) and (4,15)

The starting position of this object is at 3m where time was 0 seconds.

The velocity of this travelling object is calculated by finding the slope of the graph.

slope=velocity=Δy/Δx

Δy=15-3=12

Δx=4-0=4

m=12/4=3

velocity is 3 m/s

Learn More

Distance-time graph :brainly.com/question/8692319

Keywords : graph, titled, position,time,blue line,slope

#LearnwithBrainly

elena-s [515]4 years ago
5 0

Answer:

the answer is 4 for edg

Explanation:

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3 0
3 years ago
An object takes 2.8 years to orbit the Sun. What is its average distance (in AU) from the Sun?
Inessa05 [86]

answer look it up

Explanation:https://www.chegg.com/homework-help/questions-and-answers/takes-planet-28-years-orbit-sun-long-years-take-planet-go-way-around-sky-q29849397

5 0
3 years ago
A train moves moves from rest to a speed of 25 m/s in 30.0 sec . what is its acceleration
spayn [35]
A = Delta v/Delta t
Delta v = 25 - 0 = 25
Delta t = 30
25/30 = 5/6 = 1.66 repeating
7 0
3 years ago
Read 2 more answers
A point P is placed exactly between two charges, Q1 and Q2. If the electric field experienced by point P due to charge Q1 is 1.5
iren2701 [21]

<em>Answer:  D</em>

<em>Given data:</em>

The electric field due to charge q₁  is (E₁) = 1.5 × 10⁵ N/C

The electric field due to charge q₂ is (E₂) = 7.2 × 10⁵ N/C

Determine the net electric field at point P (Enet) = ?

electric field measured in Newtons/coulomb

<em>We know that,</em>

        The net electric field (Enet) is vector sum of E₁ and E₂ caused by the charge q₁ and q₂ respectively

             Enet = E₁ + E₂

                       = (1.5 × 10⁵)+ (7.2 × 10⁵)

                       = 8.7 × 10⁵ Newtons/coulomb

<em>The net electric field at point P is  8.7 × 10⁵ N/C</em>

4 0
4 years ago
What sport is best for someone who is 5'10, 220 lbs?
tamaranim1 [39]
Football is because 5'10 is pretty tall and 220 would be hard to tackle
7 0
3 years ago
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