A graph titled Position versus time for with horizontal axis time (seconds) and vertical axis position (meters). A straight blue
line runs with an upward slope from 0 seconds 3 meters to 4 seconds 15 meters. The starting position of this object is m. The object is traveling at a velocity of m/s.
2 answers:
a) starting position of this object is 3m
b) Velocity is 3m/s
Explanation:
The points identified on the blue line are; (0,3) and (4,15)
The starting position of this object is at 3m where time was 0 seconds.
The velocity of this travelling object is calculated by finding the slope of the graph.
slope=velocity=Δy/Δx
Δy=15-3=12
Δx=4-0=4
m=12/4=3
velocity is 3 m/s
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Distance-time graph :brainly.com/question/8692319
Keywords : graph, titled, position,time,blue line,slope
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Answer:
The velocity of each ball after the collision are 2.19 m/s and 2.58 m/s.
Explanation:
Given that,
Mass of object = 5 kg
Speed = 3 m/s
Mass of stationary object = 3 kg
Moving object deflected = 30°
Stationary object deflected = 31°
We need to calculate the velocity of each ball after collision
Using conservation of momentum
Along x-axis
Put the value into the fomrula
....(I)
Along y -axis
Put the value into the formula
...(II)
From equation (I) and (II)
Put the value of v₁ in equation (I)
Hence, The velocity of each ball after the collision are 2.19 m/s and 2.58 m/s.