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schepotkina [342]
4 years ago
8

A graph titled Position versus time for with horizontal axis time (seconds) and vertical axis position (meters). A straight blue

line runs with an upward slope from 0 seconds 3 meters to 4 seconds 15 meters. The starting position of this object is m. The object is traveling at a velocity of m/s.

Physics
2 answers:
eduard4 years ago
7 0

a) starting position of this object is 3m

b) Velocity is 3m/s

Explanation:

The points identified on the blue line are; (0,3) and (4,15)

The starting position of this object is at 3m where time was 0 seconds.

The velocity of this travelling object is calculated by finding the slope of the graph.

slope=velocity=Δy/Δx

Δy=15-3=12

Δx=4-0=4

m=12/4=3

velocity is 3 m/s

Learn More

Distance-time graph :brainly.com/question/8692319

Keywords : graph, titled, position,time,blue line,slope

#LearnwithBrainly

elena-s [515]4 years ago
5 0

Answer:

the answer is 4 for edg

Explanation:

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DochEvi [55]

Explanation:

It is given that,

Spring constant, k = 81 N/m

We need to find the force required to :

(a) Compress the spring by 6 cm i.e. x₁ = 6 cm = -0.06 m

It can be calculated using Hooke's law as :

F = - k(-x₁)

F=81\ N/m\times 0.06\ m

F = 4.86 N

(b) Expand the spring by 17 cm i.e. x₂ = 17 cm = +0.17 m

So, F = -kx₂

F=-81\ N/m\times 0.17\ m

F = -13.77 N

Hence, this is the required solution.

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3 years ago
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3 years ago
Assuming that 70 percent of the Earth’s surface is covered with water at average depth of 0.95 mi, estimate the mass of the wate
Alla [95]

Answer:

The mass of the water on earth is 5.4537\times10^{20}\ kg

Explanation:

Given that,

Average depth h= 0.95 mi

h=0.95\times1.609

h =1.528\ km

h=1.528\times10^{3}\ m

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A =4\pi r^2

Put the value into the formula

A=4\pi\times(6.37\times10^{6})^2

A=5.099\times10^{14}\ m^2

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V = Area\times height

Put the value into the formula

V=5.099\times10^{14}\times1.528\times10^{3}

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Using formula of density

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m = \rho\times V

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8 0
4 years ago
You buy a AA battery in the store, and it is marked 1.5 V. If this marking is strictly accurate, while this battery is fresh its
vitfil [10]

Answer:

Option A is correct.

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The voltage across the terminals of the battery is no longer V but is now (V) × [R/(R+r)] which is less than the initial V and it reduces as the internal resistance, r, increases.

Hope this Helps!!!

3 0
4 years ago
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Natalija [7]

Answer:

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Explanation:

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3 0
3 years ago
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