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Vlada [557]
3 years ago
9

A fluid, with a density of rho = 1165 kg/m3, flows in a horizontal pipe. In one segment of the pipe the flow speed is v1 = 4.53

m/s. In a second segment the flow speed is v2 = 1.77 m/s. What is the difference between the pressure in the second segment (P2) and the pressure in the first segment (P1)?
Physics
1 answer:
Elza [17]3 years ago
6 0

Answer:

The pressure difference between two pipe is 1.01 \times 10^{4} Pa

Explanation:

Density \rho = 1165 \frac{kg}{m^{3} }

Speed in one pipe v_{1} = 4.53 \frac{m}{s}

Speed in second pipe v_{2} = 1.77 \frac{m}{s}

According to the bernoulli equation,

The pressure difference is given by,

     P = \frac{1}{2} \rho v^{2}

P_{2} - P_{1} = \frac{1}{2}  \rho (v_{1}^{2}  - v_{2}^{2}  )

P_{2} - P_{1} = \frac{1}{2} \times 1165 \times[ (4.53)^{2}- (1.77)^{2}]

P_{2} - P_{1} = 10128.51

P_{2} - P_{1} = 1.01 \times 10^{4} Pa

Therefore, the pressure difference between two pipe is 1.01 \times 10^{4} Pa

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Answer:

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3 years ago
Direct tension indicators are sometimes used instead of torque wrenches to ensure that a bolt has a prescribed tension when used
natali 33 [55]

Complete Question

The complete question is shown on the uploaded image

Answer:

The tension on the shank is  T =8391.6 N

Explanation:

From the question we are told that

       The strain on the strain on the head is \Delta l = 0.1 mm/mm = \frac{0.1}{1000} = 0.1 *10^{-3} m/m

         The contact area is  A = 2.8 mm^2 = 2.8* (\frac{1}{1000} )^2 = 2.8*10^{-6} m^2  

Looking at the first diagram

           At  600 MPa of stress

               The strain is  0.3mm/mm

          At   450 MPa of stress

                 The strain is   0.0015 mm/mm

 To find the stress at  \Delta l we use the interpolation method

            \frac{\sigma_{\Delta l} -  \sigma_{0.0015} }{ \sigma _ {0.3} - \sigma_{0.0015} } = \frac{e_{\Delta l }  - e_{0.0015}}{e_{0.3} - e_{ 0.0015}}

Substituting values

              \frac{\sigma _{\Delta l} - 450}{600 - 450} = \frac{0.1 -0.0015}{0.3 - 0.0015}

            \sigma _{\Delta l} -450 = 49.50

             \sigma _{\Delta l} = 499.50 MPa

Generally the force on each head is mathematically represented as

              F = \sigma_{\Delta l} * A

Substituting values

             F = 499.50*10^{6} * 2.8*10^{-6}

                =1398.6N

Now the tension on the bolt shank is as a result of the force on the 6 head which is mathematically evaluated as

              T = 6 * F

                  = 6* 1398.6

              T =8391.6 N

                 

     

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The total displacement of the toy car at the given positions is 0.

The given parameters;

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The total displacement of the car is calculated as follows;

  • <em>Let the </em><em>left </em><em>direction be "</em><em>negative </em><em>direction"</em>
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\Delta x = - \ 5\ cm  \ + \ 8 \ cm \ - \ 3 \ cm \\\\\Delta x = 0

Thus, the total displacement of the toy car at the given positions is 0.

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The glowing beam was repelled by a negatively charged plate because they were negatively charged

<h3>What are the nature of charges?</h3>

The nature of charges refers to the properties of charges.

There are two types of charges:

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The law of electricity states that opposite charges attract whereas like charges repel.

Therefor, in Thomson’s experiment, the glowing beam was repelled by a negatively charged plate because they were negatively charged

In conclusion, like charges repel while opposite charges attract.

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