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Nana76 [90]
2 years ago
14

2. Does the emphasis on safety vary for each style of vehicle? In what way?

Physics
1 answer:
siniylev [52]2 years ago
8 0

Answer:

Emphasis on public safety can surely reduce the risk for various groups of population

1. Proper education and training must be provided to make them aware of the risks and how they can manage those risks.

2. Proper rules and regulation must be made and strictly followed for example traffic rules so as to avoid accidents.

3. Disaster management teams should to formed to ensure minimal loss of humans and resources during any natural calamity.

4.Eradication of poverty and illiteracy should be priority so as to ensure people focus on more important issues in life rather than involve themselves in trivial things.

Explanation:

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Ionic compounds _____.
aleksandr82 [10.1K]

Explanation:

<em>Are</em><em> </em><em>the</em><em> </em><em>compounds</em><em> </em><em>formed</em><em> </em><em>by</em><em> </em><em>the</em><em> </em><em>ionic</em><em> </em><em>bonding</em><em> </em><em>or</em><em> </em><em>electronic</em><em> </em><em>bonding</em><em>.</em><em> </em><em>They</em><em> </em><em>are</em><em> </em><em>formed</em><em> </em><em>by</em><em> </em><em>transferring</em><em> </em><em>the</em><em> </em><em>electron</em><em> </em><em>form</em><em> </em><em>one</em><em> </em><em>element's</em><em> </em><em>valance</em><em> </em><em>shell</em><em> </em><em>to</em><em> </em><em>other</em><em> </em><em>element's</em><em> </em><em>shell</em><em>.</em>

<em><u>i</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

6 0
3 years ago
X-rays with frequency 3 ⨉ 10 18 Hz shine on a crystal, producing an interference pattern. If the first bright spot is observed a
FrozenT [24]

Answer:

5.1645\times 10^{-11}\ m

Explanation:

n = Order = 1

c = Speed of light = 3\times 10^8\ m/s

f = Frequency = 3\times 10^{18}\ Hz

\theta = Angle = 75.5^{\circ}

Lattice spacing is given by

d=\dfrac{n\lambda}{2\sin\theta}\\\Rightarrow d=\dfrac{n\times c}{f2\sin\theta}\\\Rightarrow d=\dfrac{1\times 3\times 10^{8}}{3\times 10^{18}\times 2\times \sin75.5^{\circ}}\\\Rightarrow d=5.1645\times 10^{-11}\ m

The lattice spacing of the crystal is 5.1645\times 10^{-11}\ m

6 0
2 years ago
a 5-kg fish swimming at 1 m/s swallows an absent minded 1-kg fish at rest. What is the speed of the large fish immediately afyer
storchak [24]

Answer:

In first case speed of fish will be \frac{5}{6} m/s.

In the second case the speed of fish \frac{1}{6} m/s

Explanation:

Given data :-

Mass of bigger fish ( m₁ ) = 5 kg.

Mass of small fish ( m₂ ) = 1 kg.

Speed of large fish ( v₁ ) = 1 m/s

Mass of bigger fish after eating smaller one = 5 + 1 = 6 kg.

Case - 1

Momentum of bigger fish before eating the smaller fish = m₁* v₁ = 5 * 1 = 5 kg.m/s

Momentum of bigger fish after eating the larger fish = ( m₁ + m₂)*v

v = speed of bigger fish immediately after lunch.

Using the conservation of momentum.

m₁* v₁ = ( m₁ + m₂)*v

5 = 6 * v

v = \frac{5}{6}  m/s.

Case -2

Speed of small fish = 4 m/s

Momentum of bigger fish before lunch = 5 kg.m/s

Momentum of smaller fish before lunch = 4*1 = 4 kg.m/s

Net momentum before lunch = 5 - 4 = 1 kg.m/s

Momentum of bigger fish after eating the larger fish = 6 * V

Using the conservation of momentum.

1 = 6 * V

V = \frac{1}{6} m/s.

3 0
3 years ago
A mass of 150 g stretches a spring 1.568 cm. If the mass is set in motion from its equilibrium position with a downward velocity
nadezda [96]

Answer:

u(t)=\frac{1}{5} sin\ (25t)

Explanation:

Given:

  • mass of the body stretching the spring, m=150\ g
  • extension in spring, \Delta x=1.568\ cm
  • velocity of oscillation, u'(0)=20\ cm.s^{-1}
  • initial displacement position of equilibrium, u(0)=0

<u>According to given:</u>

m.g=k.\Delta x

150\times 980=k\times 1.568

k=93750\ dyne.cm^{-1}

<u>we know frequency:</u>

\omega=\sqrt{\frac{k}{m} }

\omega=\sqrt{\frac{93750}{150} }

\omega=25

Now, for position of mass in oscillation:

u= A.sin\ (\omega.t)+B.cos\ (\omega.t)

u= A.sin\ (25.t)+B.cos\ (25.t)

at t=0;\ u(0)=0\ \Rightarrow A=0

∴u(t)=B.sin\ (25.t)

∵ at t=0;\ u'(0)=20\ cm.s^{-1}\ \Rightarrow B=\frac{1}{5}

u(t)=\frac{1}{5} sin\ (25t)

7 0
3 years ago
Gas pressure in a closed system is caused by___. A. Heat given off by constant collisions.. B. Compression of the gas. C. Result
jekas [21]
Gas pressure in a closed system is caused by resultant force of all combines collisions. The correct option among all the options that are given in the question is the third option or option "C". The other options can easily be ignored. I hope the answer comes to your help.
8 0
2 years ago
Read 2 more answers
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