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2 years ago

2. Does the emphasis on safety vary for each style of vehicle? In what way?

Physics

1 answer:

siniylev [52]2 years ago

8 0

Answer:

Emphasis on public safety can surely reduce the risk for various groups of population

1. Proper education and training must be provided to make them aware of the risks and how they can manage those risks.

2. Proper rules and regulation must be made and strictly followed for example traffic rules so as to avoid accidents.

3. Disaster management teams should to formed to ensure minimal loss of humans and resources during any natural calamity.

4.Eradication of poverty and illiteracy should be priority so as to ensure people focus on more important issues in life rather than involve themselves in trivial things.

Explanation:

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A sound wave traveling through dry air has a frequency of 15 Hz, a

Korolek [52]

Answer:

Option B

Explanation:

Speed of a wave is denoted by:

v=fλ

where f is the frequency which is unchanged 15Hz and λ is the new wavelength which is 28m

v=fλ

$v=15(28)\\v=420m/s$

3 0

3 years ago

Read 2 more answers

Calculate the density of a tin of mass 100g whose dimensions are 2cmx5cmx

Luda [366]

Answer:

your question in not complete.

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7 0

2 years ago

Vitek1552 [10]

Heat energy and thermal energy are the same because heat energy is thermal energy. Also thermal energy and temperature are the same because temperature is measuring heat in degrees Celsius or degrees Fahrenheit. Hope this helps!

6 0

3 years ago

if the amplitude of sine curve is 4 and the frequency is 1 with no phase shift, what is the function that descirbes this curve?

Vlada [557]

Answer:

y = 4 Sin (2πt)

Explanation:

Amplitude, A = 4

frequency, f = 1

Wave function is given by

y = A sinωt

where, ω is angular frequency

ω = 2 π f = 2 π x 1 = 2π

So, the desired wave function

y = 4 Sin (2πt)

8 0

3 years ago

What is the efficiency (w/qh) of an ideal carnot heat engine operating between a hot region at t= 400 k and a cold one at t= 300

Vinvika [58]

The efficiency of an ideal Carnot heat engine can be written as:
$\eta = 1- \frac{T_{cold}}{T_{hot}}$
where
$T_{cold}$ is the temperature of the cold region
$T_{hot}$ is the temperature of the hot region

For the engine in our problem, we have $T_{cold}=300 K$ and $T_{hot}=400 K$ , so the efficiency is
$\eta= 1 - \frac{300 K}{400 K}=0.25$

4 0

3 years ago