Answer: 5.00 x 10^23 atoms
Explanation:
Based on Avogadro's law:
1 mole of any substance has 6.02 x 10^23 atoms
So, 1 mole of Iron = 6.02 x 10^23 atoms
0.83 moles of Iron = Z atoms
To get the value of Z, cross multiply:
Z atoms x 1mole = (6.02 x 10^23 x 0.83)
Z = 5.00 x 10^23 atoms
Thus, there are 5.00 x 10^23 atoms of iron.
Answer:
Without doing any calculations it is possible to determine that silver chromate is more soluble than <u>C,D ,</u> and silver chromate is less soluble than <u>none</u> .
It is not possible to determine whether silver chromate is more or less soluble than <u>A,B</u> by simply comparing Kspvalues
Explanation:
For this kind of question you need to obtain the balanced equation for the solubility, first, you will write the dissociation equation for every molecule, obtaining the ions in which it dissociates. Then you substitute in the Kps equation
![A_{n}B_{m} -> nA^{m+}+mB^{n-} \\K_{s}=[A^{m}]^{n}[B^{n}]^{m}](https://tex.z-dn.net/?f=A_%7Bn%7DB_%7Bm%7D%20-%3E%20nA%5E%7Bm%2B%7D%2BmB%5E%7Bn-%7D%20%5C%5CK_%7Bs%7D%3D%5BA%5E%7Bm%7D%5D%5E%7Bn%7D%5BB%5E%7Bn%7D%5D%5E%7Bm%7D)
Considering the corresponding stoichiometry you'll substitute in your dissociation equations as follow.
![Ag_{2}CrO_{4}(s)->2Ag^{+}(aq)+CrO_{4} ^{2-}\\ s ->2s+s\\s->[2s]^{2}[s]=4s^{3} \\\\A) PbF_{2}(s)->Pb^{2+} (aq)+2F^{-}\\s->s+2s\\s->[s][2s]^{2}=4s^{3}\\\\\\B)Ag_{2}SO_{3}(s)->2Ag^{+}(aq)+SO_{3} ^{2-}\\ s ->2s+s\\s->[2s]^{2}[s]=4s^{3} \\\\\\C)NiCO_{3}(s)->Ni^{2+}(aq)+CO_{3} ^{2-}\\ s ->s+s\\s->[s][s]=s^{2} \\\\\\D)AgCl(s)->Ag^{+}(aq)+Cl^{-}(aq)\\ s ->s+s\\s->[s][s]=s^{2} \\](https://tex.z-dn.net/?f=Ag_%7B2%7DCrO_%7B4%7D%28s%29-%3E2Ag%5E%7B%2B%7D%28aq%29%2BCrO_%7B4%7D%20%5E%7B2-%7D%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3E2s%2Bs%5C%5Cs-%3E%5B2s%5D%5E%7B2%7D%5Bs%5D%3D4s%5E%7B3%7D%20%20%5C%5C%5C%5CA%29%20%20PbF_%7B2%7D%28s%29-%3EPb%5E%7B2%2B%7D%20%28aq%29%2B2F%5E%7B-%7D%5C%5Cs-%3Es%2B2s%5C%5Cs-%3E%5Bs%5D%5B2s%5D%5E%7B2%7D%3D4s%5E%7B3%7D%5C%5C%5C%5C%5C%5CB%29Ag_%7B2%7DSO_%7B3%7D%28s%29-%3E2Ag%5E%7B%2B%7D%28aq%29%2BSO_%7B3%7D%20%5E%7B2-%7D%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3E2s%2Bs%5C%5Cs-%3E%5B2s%5D%5E%7B2%7D%5Bs%5D%3D4s%5E%7B3%7D%20%20%5C%5C%5C%5C%5C%5CC%29NiCO_%7B3%7D%28s%29-%3ENi%5E%7B2%2B%7D%28aq%29%2BCO_%7B3%7D%20%5E%7B2-%7D%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3Es%2Bs%5C%5Cs-%3E%5Bs%5D%5Bs%5D%3Ds%5E%7B2%7D%20%20%5C%5C%5C%5C%5C%5CD%29AgCl%28s%29-%3EAg%5E%7B%2B%7D%28aq%29%2BCl%5E%7B-%7D%28aq%29%5C%5C%20%20%20%20%20%20%20%20s%20%20-%3Es%2Bs%5C%5Cs-%3E%5Bs%5D%5Bs%5D%3Ds%5E%7B2%7D%20%20%5C%5C)
IIn this case, the silver chromate has a Kps of 
, same as the compound in options A and B, comparing these numbers you can't determine which one is bigger. Finally, options C and D have a kps of 
, this value is smaller than silver chromate's kps.
I hope you find this information useful! good luck!
It depends on the process.
Like for example if the process is isothermal(temperature is constant), you can use,
PV = constant or P1V1 = P2V2 where P1V1 are initial conditions and P2V2 are final.
For adiabatic process,
PV^gamma = constant or P1V1 ^gamma = P2V2 ^gamma.
where gamma = Cp
------
Cv
Cp = specific heat at constant pressure and Cv = specific at constant volume.
Value of Gamma will be given in question.
Hope this helps!
Answer:
a lake with a wetland fringe can fill in with decayed plant and animal material
Answer:
2.19L
Explanation:
Information from the question include:
V1 (initial volume) = 2.3L
P1 (initial pressure) = 725mmHg
P2 (final pressure) = 760mmHg
V2 (final volume) =?
With the Boyle's law equation P1V1 = P2V2, the final volume can easily be obtain as follow:
P1V1 = P2V2
725 x 2.3 = 760 x V2
Divide both side by 760
V2 = (725 x 2.3)/760
V2 = 2.19L
Therefore, the new volume of the gas at standard pressure is 2.19L
