The 4 m board's center of mass is 2 m so the pivot point is somewhere between Tasha and 2 m (if you draw a picture it's going to make this clearer)
The mass of Tasha * her distance from the pivot point = the board's mass * distance from the pivot point.
<span> Let d1 be the distance Tasha is from the pivot point. The board's center of mass from the pivot point is 2 m - d1
</span><span> 20 kg * d1 = 10 kg * (2m - d1)
</span><span> Solve for d1, you should get 2/3 of a m for the distance Tasha is from the pivot or support point. The center of mass for the board is 1 1/3 m from the support point. </span>
Object B is positively charged, Object C is negatively charged, Object D is negatively charged.
Answer:
acceleration of the car is 3 m\s^2
Explanation:
from rest means the initial velocity (vi) is zero
time = 5s
final velocity (vf) = 15m\s
a = vf - vi \ t
a = (15-0) \ 5
a= 3 m\s^2
which means that the car is speeding up 3 meters every second
Answer:
a)W= - 47.19 J
b)47.19 J
Explanation:
Given that
Weight ,mg= 71.5 N
y= 1.84 m
H= 2.5
a)
The distance above the hand ,h= 2.5 - 1.84 m
h= 0.66 m
We know that gravitaional force act in the downward direction but the displacement is in upward direction that is why work done will be negative.
W= - m g h
W= -71.5 x 0.66 J
W= - 47.19 J
b)
The potential energy at initial position = m g y
The potential energy at final position = m g H
So change in the potential energy = m g H - m g y
= mg ( H- y)
=71.5 ( 2.5 - 1.84 ) = 47.19 J
Therefore change in the potential energy = 47.19 J
Answer: The rate of energy transfer by a 5 ohms resistor when there is a current of 0.2 A in it.= 1.25 watt.
Explanation:
- The rate of energy transfer from one point to another is known as power.
- Its SI. unit is <em>Watt.</em>
Formula to compute power:
Power = 
, I = cureent, R = resistance.
Given R = 5 ohm , Current = 0.5 A.
Then, power = 
Hence, the rate of energy transfer by a 5 ohms resistor when there is a current of 0.2 A in it.= 1.25 watt.
