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suter [353]
4 years ago
13

The statements in the tables below are about two different chemical equilibria. The symbols have their usual meaning, for exampl

e AG Gibbs free energy of reaction and stands for the equilibrium constant. stands for the standard In each table, there may be one statement that is false because it contradicts the other three statements. If you find a false statement, check the box next to It. Otherwise, check the "no false statements box under the table. statement false? statement false? Ink>0
AH° R<1
AG'>0
AG'>0
In > AH">TAS
no false statements

Chemistry
1 answer:
Talja [164]4 years ago
4 0

Answer:

see explaination

Explanation:

Please kindly check attachment for the step by step solution of the given problem

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The specific heat of liquid bromine is 0.226 J/g-K. How much heat (J) is required to raise the temperature of 10.0 mL of bromine
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Answer:

16.2 J

Explanation:

Step 1: Given data

  • Specific heat of liquid bromine (c): 0.226 J/g.K
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  • Final temperature: 27.30 °C
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Step 2: Calculate the mass of bromine

The density is equal to the mass divided by the volume.

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m = ρ × V

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Step 3: Calculate the change in the temperature (ΔT)

ΔT = 27.30 °C - 25.00 °C = 2.30 °C

The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.

Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine

We will use the following expression.

Q = c × m × ΔT

Q = 0.226 J/g.K × 31.2 g × 2.30 K

Q = 16.2 J

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