Answer:
THE MOLARITY OF THE SOLUTION IS 0.1039 MOL/DM3
Explanation:
Molarity is the number of moles of solute in a given solution,
Molarity in mol / dm3 = Molarity in g/dm3 / Molar mass
Mass = 15.2 g
Volume of solution = 2.5 l
Molar mass of NaCl = (23 + 35.5) = 58.5 g/mol
First, we calculate the molarity in g/dm3
Molarity in g/dm3 = mass /volume
= 15.2 g * 1 L / 2.5 L
=6.08 g /dm3
Hence, we will introduce the values and solve for molarity in mol/dm3
Molarity = 6.08 g/dm3/ 58.5 g/mol
Molarity = 0.1039 mol/dm3
The molarity of the solution is 0.1039 mol/dm3
