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guajiro [1.7K]
2 years ago
6

If i go to the moon what happens to my mass and weight

Physics
1 answer:
mixas84 [53]2 years ago
6 0

Your mass stays the same because mass is the matter of something so the only way it could be changed is if you cut off something

Your weight changes because the gravitational field strength of different

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A small uniform disk and a small uniform sphere are released simultaneously at the top of a high inclined plane, and they roll d
barxatty [35]

Answer:

(D) the sphere

Explanation:

The bodies given are Disk and Solid sphere (uniform sphere)

Moment of inertia of the bodies are

I(disk) = \frac{MR^2}{2}

I(sphere) = \frac{2MR^2}{5}

Since the moment of inertia of sphere is less than that of disk, therefore sphere will reach the bottom first.

3 0
3 years ago
What does that make?
Kobotan [32]

Answer:

lithium

Explanation:

A lithium atom contains 3 protons in its nucleus irrespective of the number of neutrons or electrons. Notice that because the lithium atom always has 3 protons, the atomic number for lithium is always 3. The mass number, however, is 6 in the isotope with 3 neutrons, and 7 in the isotope with 4 neutrons.

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2 years ago
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An oven uses 4500 watts of power in 2 minutes, how much work was done?
jolli1 [7]
First of all we state the formula
Power=work done/time
we can rearrange this formula as well
work done=power x time

Since the SI unit of time is in seconds we change the minutes to seconds
2mins= 60x2 = 120 seconds

Using our formula (work done=power x time) we simply put in the values
work done = 4500 x 120
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4 0
2 years ago
What is 1 abiotic factors shown in this diagram?
yawa3891 [41]

Answer:

B. The water

Explanation:

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7 0
3 years ago
Ted Clubber Lang. A hook in boxing primarily involves horizontal flexion of the shoulder while maintaining a constant angle at t
il63 [147K]

Answer:

15 m/s or 1500 cm/s

Explanation:

Given that

Speed of the shoulder, v(h) = 75 cm/s = 0.75 m/s

Distance moved during the hook, d(h) = 5 cm = 0.05 m

Distance moved by the fist, d(f) = 100 cm = 1 m

Average speed of the fist during the hook, v(f) = ? cm/s = m/s

This can be solved by a very simple relation.

d(f) / d(h) = v(f) / v(h)

v(f) = [d(f) * v(h)] / d(h)

v(f) = (1 * 0.75) / 0.05

v(f) = 0.75 / 0.05

v(f) = 15 m/s

Therefore, the average speed of the fist during the hook is 15 m/s or 1500 cm/s

6 0
3 years ago
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