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krok68 [10]
2 years ago
9

A sportscar has a mass of 1500 kg and accelerates at 5 meters per second squared. What is the magnitude of the force acting on t

he sportscar?
Physics
1 answer:
Hatshy [7]2 years ago
4 0

Answer:

7500 Newtons

Explanation:

Mass of the sportscar= 1500 kg

Acceleration of the sportscar= 5m/s^2

Hence, let the Force acting on it be F

We\ know\ that,\\Force=Mass*Acceleration\\F=ma\\\\Here,\\F=1500*5\\=7500 kg m/s^2\ or\ 7500\ Newtons

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Turbine generators to produce electricity. 
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In a video game, a ball moving at 0.6 meter/second collides with a wall. After the collision, the velocity of the ball changed t
kolezko [41]
Using F=m(v-u) /t

where f=ma
Ma = m(v-u)/t
a = (v-u) /t
a= (-0.4-0.6)/0.2
a= -1/0.2 = -5ms-² (it's decelerating)
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A uniform circular disk has a radius of 34 cm and a mass of 350 g. Its center is at the origin. Then a circular hole of radius 6
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4 0
3 years ago
A long, thin solenoid has 450 turns per meter and a radius of 1.17 cm. The current in the solenoid is increasing at a uniform ra
sergey [27]

Answer:

\frac{di}{dt}  = 7.31 \  A/s

Explanation:

From the question we are told that  

     The  number of turns is  N =  450 \  turns

      The  radius is  r =  1.17 \ cm =  0.0117 \ m

       The  position from the center consider is  x =  3.45 cm  =  0.0345 m

       The  induced emf is  e  =  8.20 *10^{-6} \  V/m

Generally according to Gauss law

        \int\limits { e } \, dl  =  \mu_o *  N  *  \frac{di}{dt }  *  A

=>    e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  A

Where A is the  cross-sectional area of the solenoid which is mathematically represented as

                A =  \pi r ^2

=>      e *  2\pi x  =  \mu_o  *  N  *  \frac{d i }{dt }  *  \pi r^2

=>       \frac{di}{dt}  =  \frac{2e * x  }{\mu_o * N  * r^2}ggl;

Here  \mu_o is the permeability of free space with value

          \mu_o  =  4\pi * 10^{-7} \  N/A^2

=>     \frac{di}{dt}  =  \frac{2 *  8.20*10^{-6} *  0.0345  }{ 4\pi * 10^{-7} * 450  * (0.0117)^2}

=>      \frac{di}{dt}  = 7.31 \  A/s

6 0
3 years ago
On a frictionless air track, a blue glider with mass 0.200 kg is moving to the right with a speed of 8.00 m/s. It strikes a red
Crank

Answer:a) v = 0.33 to the right.

b) No, it is inelastic

Explanation: mass of blue glider = 0.2kg,

initial velocity of blue glider = 8m/s

Mass of red glider = 0.6 kg

initial velocity of glider = 0 ( since it is at rest)

Final velocity of blue glider after collision = 2 m/s.

Final velocity of the red glider after collision =?

Law of conservation of momentum states vector sum of momentum before collision equals vector sum after collision.

Before collision

(0.2×8) + (0.6×0) = 1.6 + 0 = 1.6 m/s

After collision

they will both move in opposite direction, since blue glider moved left, red glider will move right. Since the blue glider moved in the opposite direction (left), it momentum will be negative and that of red will be positive

-(0.2×2) + 0.6v = 6v - 0.4

By equating them both

1.6 = 6v - 0.4

1.6 + 0.4 = 6v

2 = 6v, v = 2/6

v = 0.33 to the right.

B)

Sum of kinetic energy before collision

1/2 ×(0.2) × 8² + 1/2 × 0.6 × 0

1/2 × 0.2 × 64 = 6.4 J.

Sum of kinetic energy after collision

1/2 × (0.2) ×2² + 1/2 ×(0.6) ×(0.3)²

{1/2 × 0.2 ×4} + 1/2 × 0.6 × 0.09

0.4 + 0.027 = 0.427.

No

Since the kinetic energy before and after collision are not equal, then the collision is inelastic that's the collision is not elastic

5 0
3 years ago
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