Question

A flea jumps straight up to a maximum height of 0.470 m . What is its initial velocity v0 as it leaves the ground?

Answer 1

We use kinematic equation,

$v^2_{f} = v^2_{0} + 2 a s$

Here, $v_{f}$ is final velocity and a is acceleration and s is maximum height.

Given,  $s = 0.470 \ m$ and we take a as negative value of acceleration due to gravity $( - 9.8 \ m/s^2)$.

At the maximum height, final velocity is zero.

Substituting these values in above equation, we get

$0 = v^2_{0} + 2(-9.8 \ m/s^2)0.470 \ m \\\\ v^2_{0} = 9.2 (m/s)^2 \\\ v_{0} = 3.03 m/s$

Therefore, the initial velocity with it leave the ground is 3.03 m/s.